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zloy xaker [14]
3 years ago
12

Find JQ if Q is the incenter of JLN

Mathematics
1 answer:
melamori03 [73]3 years ago
6 0

Answer:

Find each measure. 9. NP. ANSWER: 14. 10. PS.

Step-by-step explanation:

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4,320 is divisible by?<br> 3<br> 9<br> 10
marusya05 [52]

Answer:

3, 9, and 10

Step-by-step explanation:

To figure out whether 4,320 is divisible by these numbers, we can use their <em>divisibility rules</em> to help us out.

A number is divisible by 3 or 9 if its digits add up to a number divisible by 3 or 9. The digits of 4,320 add to 4 + 3 + 2 + 0 = 9, which is divisible by both 3 and 9, so <em>4,320 is divisible by 3 and 9</em>.

A number is divisible by 10 if its last digit is a 0, which we have here, so <em>4,320 is divisible by 10</em>.

5 0
3 years ago
Read 2 more answers
10 POINTS I WILL GIVE BRAINLIEST
natima [27]

Answer:

arithmetic sequence

A sequence with the difference between two consecutive terms constant. The difference is called the common difference.

Step-by-step explanation:

8 0
3 years ago
A ship is stationary at sea.
Andrei [34K]

Answer:

The distance between the yacht from the ship is about 33.6 km.

Step-by-step explanation:

The diagram is attached below.

Point A is the shipe, Point B is the tugboat, and Point C is the yacht.

Since the tugboat is 28 km away, and the scale being used is 1 cm : 4 km, the tugboat is 7 cm away from the ship at a 210° bearing on the diagram.

Likewise, the yacht is 6 cm away from the tugboat at a 210° bearing.

To find the distance between the yacht to the ship, we need to determine the value of <em>x</em>.

To do so, we can use the Law of Cosines:

b^2=a^2+c^2-2ac\cos(B)

First, we need to determine ∠B.

A has a bearing of 210°. 180° is covered by QI and IV. So, the small angle in QIII is 30°.

By Alternate Interior Angles, the angle in QI (inside the triangle) of Point B must also be 30°.

And since Point B has a bearing of 310°, 270° is covered in total by QI, QIV, and QIII. So, 40° is left in QII.

Therefore, 50° is the measure of the angle in QIII within the triangle of Point B.

Thus, ∠B measures 50° + 30° = 80°.

So, ∠B measures 80°. We also know that <em>a</em> = 6 and <em>c</em> = 7. Substitute:

b^2=(6)^2+(7)^2-2(6)(7)\cos(80)

Simplify and take the square root of both sides. So:

b=\sqrt{85-84\cos(80)}

Approximate using a calculator:

b=8.3912...\approx 8.39\text{ cm}

Since 1 cm : 4km, to find the distance in km, we simply need to multiply by four. So:

\Rightarrow b=4(8.3912...)=33.5651\approx 33.6\text{ km}

The distance between the yacht from the ship is about 33.6 km.

7 0
3 years ago
SHOW YOUR WORK,Solve this system of equations for x using the addition method
maria [59]

Answer:

NUMBER 1.)

Step 1

Subtract 3y3y from both sides.

5x=10-3y5x=10−3y

Step 2

Divide both sides by 55.

\frac{5x}{5}=\frac{10-3y}{5}

5

5x

=

5

10−3y

Hint

Undo multiplication by dividing both sides by one factor.

Step 3

Dividing by 55 undoes the multiplication by 55.

x=\frac{10-3y}{5}x=

5

10−3y

Hint

Undo multiplication.

Step 4

Divide 10-3y10−3y by 55.

x=-\frac{3y}{5}+2x=−

5

3y

+2

Hint

Divide.

Solution

x=-\frac{3y}{5}+2x=−5

3y+2

Step-by-step explanation:

NUMBER 2.)

Step 1

Add 4y4y to both sides.

3x=6+4y3x=6+4y

Step 2

The equation is in standard form.

3x=4y+63x=4y+6

Step 3

Divide both sides by 33.

\frac{3x}{3}=\frac{4y+6}{3}

3

3x

=

3

4y+6

Hint

Undo multiplication by dividing both sides by one factor.

Step 4

Dividing by 33 undoes the multiplication by 33.

x=\frac{4y+6}{3}x=

3

4y+6

Hint

Undo multiplication.

Step 5

Divide 6+4y6+4y by 33.

x=\frac{4y}{3}+2x=

3

4y

+2

Hint

Divide.

Solution

x=\frac{4y}{3}+2x= 3

4y+2

4 0
3 years ago
NEED HELP PLEASEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE
padilas [110]

Answer:

A

Step-by-step explanation:

The function has vertical asymptotes at x=7 and x=-3, so the denominator needs to have factors (x-7) and (x+3).

This eliminates all the options except for A.

3 0
2 years ago
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