Question

SHOW YOUR WORK,Solve this system of equations for x using the addition method

Answer 1

Answer:

NUMBER 1.)

Step 1

Subtract 3y3y from both sides.

5x=10-3y5x=10−3y

Step 2

Divide both sides by 55.

\frac{5x}{5}=\frac{10-3y}{5}

5

5x

=

5

10−3y

Hint

Undo multiplication by dividing both sides by one factor.

Step 3

Dividing by 55 undoes the multiplication by 55.

x=\frac{10-3y}{5}x=

5

10−3y

Hint

Undo multiplication.

Step 4

Divide 10-3y10−3y by 55.

x=-\frac{3y}{5}+2x=−

5

3y

+2

Hint

Divide.

Solution

x=-\frac{3y}{5}+2x=−5

3y+2

Step-by-step explanation:

NUMBER 2.)

Step 1

Add 4y4y to both sides.

3x=6+4y3x=6+4y

Step 2

The equation is in standard form.

3x=4y+63x=4y+6

Step 3

Divide both sides by 33.

\frac{3x}{3}=\frac{4y+6}{3}

3

3x

=

3

4y+6

Hint

Undo multiplication by dividing both sides by one factor.

Step 4

Dividing by 33 undoes the multiplication by 33.

x=\frac{4y+6}{3}x=

3

4y+6

Hint

Undo multiplication.

Step 5

Divide 6+4y6+4y by 33.

x=\frac{4y}{3}+2x=

3

4y

+2

Hint

Divide.

Solution

x=\frac{4y}{3}+2x= 3

4y+2