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3 years ago

Helpppp plsssss someone !!!!!

Mathematics

1 answer:

Ilia_Sergeevich [38]3 years ago

5 0

The answer is b I really. Don’t know don’t trust me

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David owns 24% of a partnership. Robert owns 48% of the partnership. If Sam is the third partner, what percent of the partnershi

Tanya [424]

Answer:

28%

Step-by-step explanation:

100-72= 28%

7 0

2 years ago

Read 2 more answers

-3y + 8x = 36<br> 6x + y = -21

tiny-mole [99]

Answer:

x=−27/26

and y=−192/13

Step-by-step explanation:

6x+y=−21;8x−3y=36

Step: Solve6x+y=−21for y:

6x+y=−21

6x+y+−6x=−21+−6x(Add -6x to both sides)

y=−6x−21

Step: Substitute−6x−21foryin8x−3y=36:

8x−3y=36

8x−3(−6x−21)=36

26x+63=36(Simplify both sides of the equation)

26x+63+−63=36+−63(Add -63 to both sides)

26x=−27

26x

−27

(Divide both sides by 26)

7 0

3 years ago

From experience, it is known that on average 10% of welds performed by a particular welder are defective. if this welder is requ

bulgar [2K]

Binomial distribution can be used because the situation satisfies all the following conditions:1. Number of trials is known and remains constant (n)2. Each trial is Bernoulli (i.e. exactly two possible outcomes) (success/failure)3. Probability is known and remains constant throughout the trials (p)4. All trials are random and independent of the othersThe number of successes, x, is then given by $P(x)=C(n,x)p^x(1-p)^{n-x}$ where $C(n,x)=\frac{n!}{x!(n-x)!}$
Here we're given
p=0.10 [ success = defective ]
n=3

(a) x=0
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,0)0.1^0(1-0.1)^{3-0}$
$=1(1)(0.729)$
$=0.729$

(b) x=2
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,2)0.1^2(1-0.1)^{3-2}$
$=3(0.01)(0.9)$
$=0.027$

(c) x ≥ 2
$P(x)=\sum_{x=2}^3C(n,x)p^x(1-p)^{n-x}$
$=P(2)+P(3)$
$=C(n,2)p^2(1-p)^{n-2}+C(n,3)p^3(1-p)^{n-3}$
$=C(3,2)0.1^2(1-0.1)^{3-2}+C(3,3)0.1^3(1-0.1)^{3-3}$
$=3(0.01)(0.9)+1(0.001)1$
$=0.027+0.001$
$=0.028$

8 0

3 years ago

Find the coordinates of the midpoint M of the segment with the given endpoints. Then find the distance between the two points. R

Mrac [35]

Answer:

Midpoint (-2,4)

distance nearest tenth = 8.9

The approximate distance = 9

Step-by-step explanation:

Formulas

PQ midpoint = (x2 + x1)/2, (y2 + y1)/2

distance d = sqrt( (x2 - x1)^2 + (y2 - y1)^2 )

Givens

x2 = -4

x1 = 0

y2 = 1

y1 = 7

Solution

M(PQ) = (-4+0)/2, (1 + 7)/2

M(PQ) = -2, 4

The midpoint is -2,4

The distance = sqrt( (4 - 0)^2 + (1 + 7)^2 )

The distance = sqrt(16 + 64)

The distance = sqrt(80)

The distance = 4√5 exactly

The distance = 8.94

The distance = 8.9 To the nearest tenth

Question 2

The distance is rounded to the nearest whole number which is 9.

6 0

3 years ago

On a sunny afternoon, a 10-meter tall billboard casts a shadow that is 6 meters long. At the same time a nearby building casts a

Liono4ka [1.6K]

1) 10/6 = H/ 4 or 5/3 = H/2 or H = 10/3 = 3.3 m

<span>2) sin P = 3/5 (given) = sin (90-Q) = cos Q = 3/5</span>

5 0

3 years ago