All categories

3 years ago

I need help simplifying this expression ( 7y - 8 + 6y - 3) please explain thanks !

Mathematics

2 answers:

Anit [1.1K]3 years ago

5 0

(7y-8+6y-3)
=(13y-11)

Anon25 [30]3 years ago

3 0

7y - 8 + 6y - 3
= 13y - 11

-----------------

7y + 6y = 13y
(-8) + (-3) = -11

You might be interested in

How do you solve this

brilliants [131]

First, ask somebody else like your teacher, also use your brain

5 0

3 years ago

Your monthly living expenses are $1500 on an income of $1,650 per month. Your goal is to have an emergency fund of 4 times your

DochEvi [55]

Your end goal is to have $6000 total in 12 months. since you have $2400 already you can subtract that from 6000 leaving you with $3600 over the course of 12 months. since you already put $150 in a month over the course of 12 months you would have $1800 which is only half of the goal of $3600. in order for you to put in $3600 you would have to put an additional 150 in your savings along with your regular 150 making the answer b.

6 0

4 years ago

Read 2 more answers

Three million and nine thounsandths

nika2105 [10]

One million = 1,000,000

So Three million is 3,000,000

One thousandths is 0.001

So nine thousandths is 0.009

So three million and nine thousandths is 3,000,000.009

5 0

3 years ago

Read 2 more answers

Im kinda confused on this. i need help.

RideAnS [48]

Given :-

A graph is given to us .

To Find :-

The equation in slope intercept form .

Answer :-

From the given graph , we can see that the line passes through y axis at (0,5) . So the y intercept is 5 . And the slope of the line is 5/2 = 2.5 . So ,

$\sf\longrightarrow$ y intercept = 5 .

$\sf\longrightarrow$ slope = 5/2 .

Now here we can use the slope intercept form as ,

$\sf\longrightarrow$ y = mx + c

$\sf\longrightarrow$ y = 5/2x + 5

Hence the required answer is y = 5/2x + 5.

4 0

2 years ago

Read 2 more answers

In triangle $ABC$, let angle bisectors $BD$ and $CE$ intersect at $I$. The line through $I$ parallel to $BC$ intersects $AB$ and

Umnica [9.8K]

Answer:

Step-by-step explanation:

If you work through a series of obscure calculations involving area and the radius of the incircle, they boil down to a simple fact:

... For MN║BC, perimeter ΔAMN = perimeter ΔABC - BC = AB+AC

.. = 17+24 = 41

_____

Wow! Thank you for an interesting question with a not-so-obvious answer.

_____

A little more detail

The point I that you have defined is the incenter—the center of an inscribed circle in the triangle. Its radius is the distance from I to any side, such as BC, for example.

If we use "Δ" to represent the area of the triangle and "s" to represent the semi-perimeter, (AB+BC+AC)/2, then the incircle has radius Δ/s. The area Δ can be computed from Heron's formula by ...

... Δ = √(s(s-a)(s-b)(s-c)) . . . . where a, b, c are the side lengths

For this triangle, the area is Δ = √38480 ≈ 196.1632 units². That turns out to be irrelevant.

The altitude to BC will be 2Δ/(BC), so the altitude of ΔAMN = (2Δ/(BC) -Δ/s). Dividing this by the altitude to BC gives the ratio of the perimeter of ΔAMN to the perimeter of ΔABC, which is 2s.

Putting these ratios and perimeters together, we get ...

... perimeter ΔAMN = (2Δ/(BC) -Δ/s)/(2Δ/(BC)) × 2s

... = (2/(BC) -1/s) × BC × s = 2s -BC

... perimeter ΔAMN = AB +AC

8 0

3 years ago