Answer:
![\[t\leq -13\]](https://tex.z-dn.net/?f=%5C%5Bt%5Cleq%20-13%5C%5D)
Step-by-step explanation:
Given inequality is ![\[−3t\geq39\]](https://tex.z-dn.net/?f=%5C%5B%E2%88%923t%5Cgeq39%5C%5D)
Simplifying:
![\[-t\geq \frac{39}{3}\]](https://tex.z-dn.net/?f=%5C%5B-t%5Cgeq%20%5Cfrac%7B39%7D%7B3%7D%5C%5D)
![\[=>-t\geq13\]](https://tex.z-dn.net/?f=%5C%5B%3D%3E-t%5Cgeq13%5C%5D)
Sign of the inequality changes of making both sides negative.
![\[=>t\leq -13\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Et%5Cleq%20-13%5C%5D)
Hence the solution for the given inequality is represented by
This means that the original inequality will be true only for those values of t which are less than or equal to -13.
Answer:
pythagoren therom, law of sine, cosine, and tangent
Step-by-step explanation:
English please ? I only speak English but I’m sure I can help.
Answer:
Our answer is 0.8172
Step-by-step explanation:
P(doubles on a single roll of pair of dice) =(6/36) =1/6
therefore P(in 3 rolls of pair of dice at least one doubles)=1-P(none of roll shows a double)
=1-(1-1/6)3 =91/216
for 12 players this follows binomial distribution with parameter n=12 and p=91/216
probability that at least 4 of the players will get “doubles” at least once =P(X>=4)
=1-(P(X<=3)
=1-((₁₂ C0)×(91/216)⁰(125/216)¹²+(₁₂ C1)×(91/216)¹(125/216)¹¹+(₁₂ C2)×(91/216)²(125/216)¹⁰+(₁₂ C3)×(91/216)³(125/216)⁹)
=1-0.1828
=0.8172
Answer: I think -131
Step-by-step explanation:
