So the problems ask to find and calculate the exact value of the trigonometric equation in the following equations and the best answers would be the following:
#1. sqrt(3)/3
#2. Arcsine of zero is 0
#3. x/sqrt(4-x^2)
I hope you are satisfied with my answer and feel free to ask for more if you have questions and further clarifications. Have a nice day
Answer:
x = -1, x = 1
Step-by-step explanation:
Factor the equation. (It's a difference of squares, so we know the form will be (a-b)(a+b).)
Test this by FOILing it out, if you're unsure. This is something it can be good to memorize!
Set it equal to 0.
Separate the two parenthetical expressions by the Zero Product Property.
Solve for x!
Answer:
can u please type out the photo is too dark to see the questions
Step-by-step explanation:
For this case what you must do is find the diagonal of the square to find the diameter of the circle and then be able to obtain the radius.
We have then:
A = L ^ 2 = 128
L = root (128)
L = 11.3137085
Then, the diagonal of the square knowing its sides is:
d = root ((L) ^ 2 + (L) ^ 2)
d = root ((11.3137085) ^ 2 + (11.3137085) ^ 2)
d = 16 feet
Finally the radius of the circle is:
r = d / 2
r = (16) / 2
r = 8feet
answer:
the radius of the circle is
r = 8feet
Answer:
C = 22π; A = 121π.
Step-by-step explanation:
To find the circumference of a circle, you do pi times the diameter. That would be 22pi.
To find the area of a circle, you do pi * r^2. The radius is the diameter divided by 2. That is 22 / 2, which is 11. Then, the area would be pi * 11^2 = pi * 121 = 121pi.
So, C = 22pi; A = 121pi.
Hope this helps!
