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lidiya [134]
3 years ago
13

Which is the solution to the equation represented by the model below

Mathematics
2 answers:
Kruka [31]3 years ago
5 0

Answer:

Third option, x=2

Step-by-step explanation:

By observation, we can infer that

3x+8=4x+6.

Subtract 8 from both sides:

3x+8-8=4x+6-8

3x=4x-2

Subtract 4x from both sides:

3x-4x=4x-2-4x

-x=-2

Divide both sides by -1:

\frac{-x}{-1}=\frac{-2}{-1}

x=2

Snowcat [4.5K]3 years ago
4 0

Answer:

c; x=2

Step-by-step explanation:

You can see that there are 3 x's and 8 1's (3x+8), as well as 4 x's and 6 1's (4x+6).

The equation is 3x+8=4x+6

Subtract 3x and subtract 6: 2=x

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Explain whether the following given sets are closed under addition:
Ivan

Answer:

Step-by-step explanation:

a) Yes.

\forall\ a,b\ \in\ B,\ a+b\in B\ (since\ 0+0=0)

b) Yes

W=\{0,1,2,3,..,\}\ (whole\ numbers)\\\forall\ a,b\ \in\ 3W,\ a+b\in 3W\\since:\\a\ \in\ 3W \Longrightarrow\ \exists\ k_1\in W | a=3*k_1\\\\b\ \in\ 3W \Longrightarrow\ \exists\ k_2\in W | b=3*k_2\\\\a+b=3*k_1+3*k_2=3*(k_1+k_2) \in 3W\\

c) Yes

\forall n\ \in\ \mathbb{N}: \Longrightarrow\ n+1 \in\ \mathbb{N}\\

d) No

3\in V , 3+3=6\notin V\\

7 0
3 years ago
Can someone help me?<br><br><br>2x-3y= -1 <br>y=x-1<br><br>​
MrRissso [65]
X=4 & y=3

Explanation:

Picture
5 0
2 years ago
The equation x^3+x^2+ax-4=0 has one root equal to -2. Find the value of a.​
Vedmedyk [2.9K]

Answer:

a = - 4

Step-by-step explanation:

Given x = - 2 is a root then f(- 2) = 0

f(x) = x³ + x² + ax - 4, thus

f(- 2) = (- 2)³ + (- 2)² - 2a - 4 = 0, that is

f(- 2) = - 8 + 4 - 2a - 4 = 0, thus

- 8 - 2a = 0 ( add 8 to both sides )

- 2a = 8 ( divide both sides by - 2 )

a = - 4

5 0
3 years ago
Which equation is true when n = 4?<br> A<br> 2n = 6<br> Bn+3 = 7<br> 9- n = 13
kari74 [83]

Answer:

The answer is B. n+3=7

Step-by-step explanation:

^^^^^^^

5 0
3 years ago
Read 2 more answers
If the equation y = 3x + 2 is changed to y = -3x + 2, how will the graph of the line change?
MrRissso [65]
The line will flip across the y-axis.
7 0
3 years ago
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