There are no such examples on the list you've provided.
Answer:
C) It increases to 2.0 cm
Explanation:
In a double-slit diffraction experiment, the distance on the screen between two adjacent maxima is given by
where
is the wavelength of the wave
D is the distance of the screen from the slits
d is the separation between the slits
In this problem, the initial distance between adjacent maxima is 1.0 cm. Later, the slit separation is cut in a half, which means that the new slit separation is
Substituting into the equation, we find that the new separation between the maxima is
So, the distance increases by a factor 2: therefore, the new separation between the maxima will be 2.0 cm.
<h3>Answer:- </h3><h3>16000 </h3><h3> Explanation:-</h3><h3 /><h3>force = 800N</h3><h3>area of 1 feet = 0.025</h3><h3>Area of 2 feet= 0.025+0.025 = 0.050m²</h3><h3>presure = force / area </h3><h3> = 800 N / 0.050</h3><h3> = 16000</h3>
Answer:
b. 450 nm
Explanation:
The wavelength of light can be calculated by using the formula derived in Young's double slit experiment. The formula is as follows:
Δx = λL/d
Δx/2 = λL/2d
where,
Δx/2 = half distance between consecutive dark fringes = width of central maximum = 0.75 cm = 0.0075 m
λ = wavelength of light = ?
L = Distance of Screen = 1.25 m
d = width of slit = 0.15 mm = 0.00015 m
Therefore,
0.0075 m = λ(1.25 m)/(0.00015 m)
λ = (0.0075 m)(0.00015 m)/2(1.25 m)
λ = 4.5 x 10⁻⁷ m = 450 nm
Thus, the correct option is:
<u>b. 450 nm</u>
Answer:
upthrust or BUOYANT FORCE =Vdg
volume=LWH
upthrust=(4cm×5cm×2cm)×1g/cm²×g
upthrust=40cm³×1g/cm³×g
upthrust=40gf or 0.04kg×10m/s²=0.4N
weight of the displaced liquid is upthrust.
so mass=40g or 0.04kg
upthrust=40gf or 0.4Nand mass of the displaced liquid=40g or 0.04kg
please mark brainliest, hope it helped
