Answer:
v = 3.53x10⁻³ m/s.
Explanation:
We can find the velocity of the rock by energy conservation:
Where:
<em>i</em> is for initial and<em> f</em> is for final
k: is the stiffness of the rubber = 20 N/m
x: is the distance of the rubber compression = 5 mm = 0.005 m
m: is the mass of the stone = 40 kg
v: is the velocity =?
Hence, the velocity is:
Therefore, the velocity with which the stone leaves the catapult is 3.53x10⁻³ m/s.
I hope it helps you!
