All categories

2 years ago

Find a number that would make the equation true: 15 + _ = -15

Mathematics

2 answers:

sergey [27]2 years ago

7 0

The answer is -30

-30 + 15 =-15

lidiya [134]2 years ago

7 0

Answer:

15 + _ = -15

15 + 15 = _

- 30 = _

- 30 is the answer.

You might be interested in

There are 45 animals at the pet store. 12% are dogs, 24% are cats, 36% are fish, and 28% are other animals. Find the number of a

vivado [14]

Step-by-step explanation:

Dogs: 12% of 45= 5.4

Cats: 24% of 45= 10.8

Fish: 36% of 45= 16.2

Other: 28% of 45= 12.6

8 0

3 years ago

Use implicit differentiation to find y^1 for the equation y^2-y-4x=0

Rudik [331]

Answer:

Step-by-step explanation:

y²-y-4x=0

differentiate w.r.t. x

2y*y^1-y^1-4=0

(2y-1)y^1=4

y^1=4/(2y-1)

3 0

3 years ago

Please help I will give out brainliest

Licemer1 [7]

Answer:

Step-by-step explanation:

Our function is : 3x²-3x-1

3x²-3x+2=2
3x²-3x-1+3=2
3x²-3x-1= -1
the number that gives us -1 is 1 (from the graph)

so x is 1

3x²-3x-1= x+1 ⇒3x²-4x-2 = 0
Δ(the dicriminant)= (-4)²-4*3*(-2)= 16+24 =40
two solution x and y
x= (4-√40)/6 and y= (4+√40)/6
x= -0.38 and y = 1.7
so the estimations are -0.38 and 1.7

6 0

3 years ago

Can anyone help me with part C?

finlep [7]

Answer:430

Step-by-step explanation:78 times 3 is 430

3 0

3 years ago

Two pieces of equipment were purchased for a total of $4000. If one piece cost $850 more than

ruslelena [56]

The price of less expensive equipment is $1575.

Step-by-step explanation:

Let,

Price of one equipment = x

Price of other equipment = y

According to given statement;

x+y=4000 Eqn 1

x = y+850 Eqn 2

Putting Eqn 2 in Eqn 1

$(y+850)+y=4000\\y+850+y=4000\\2y=4000-850\\2y=3150$

Dividing both sides by 2;

$\frac{2y}{2}=\frac{3150}{2}\\y=1575$

Putting y=1575 in Eqn 2;

$x=1575+850\\x=2425$

The price of less expensive equipment is $1575.

Keywords: linear equation, substitution method

Learn more about linear equations at:

#LearnwithBrainly

3 0

3 years ago