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2 years ago

Answer question 14 please

Mathematics

1 answer:

Fittoniya [83]2 years ago

7 0

Answer:

Step-by-step explanation:

Z is the only relation that does not pass the vertical line test, so Z is not a function.

Answer: D

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($2000) x 0.06 + ($3000) x 0.08 = $360
Thus, the amount of the total interest is $360.

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3 years ago

Leatherbound Stores, Inc., rejects a shipment of goods that does not conform to its contract with Cowhide Corporation, but is un

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Step-by-step explanation:

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3 years ago

What is a net in math?

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2 years ago

Read 2 more answers

Test the claim that the mean GPA of night students is larger than 3.1 at the .10 significance level. The null and alternative hy

Alborosie

Answer:

H 0 : μ = 3.1 H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

$t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66$

$df = n-1=75-1 =74$

The p value is:

$p_v = P(t_{74} >8.66) =3.65x10^{-13}$

The significance level is: 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

Step-by-step explanation:

For this case we want to test the claim that mean GPA of night students is larger than 3.1 at the .10 significance level. The claim needs to be on the alternative hypothesis so then we have the following system of hypothesis:

H 0 : μ = 3.1 H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

We have the following info given:

$\bar X = 3.13 , s =0.03 , n =75$

The statistic to check the hypothesis is given by:

$t = \frac{\bar X -\mu}{\frac{s}{\sqrt{n}}}$

Replacing the info given we got:

$t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66$

The degrees of freedom are given by:

$df = n-1=75-1 =74$

The p value since is a right tailed ted is given by:

$p_v = P(t_{74} >8.66) =3.65x10^{-13}$

The significance level is 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

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3 years ago

A science fair poster is very rectangular 3 feet long and 2 feet wide what is the area of the poster in square inches

pantera1 [17]

You want to do base × height to get your answer
3×2 = 6
So the area of the poster is 6 sq in.

If this helps pls mark brainliest pts

8 0

3 years ago