Given:
![y=\frac{x+2}{5}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7Bx%2B2%7D%7B5%7D)
Required:
We need to find the domain of the given function if it is a function.
Explanation:
We need to graph the given equation.
Set x =3 and substitute in the given equation.
![y=\frac{3+2}{5}=\frac{5}{5}=1](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B3%2B2%7D%7B5%7D%3D%5Cfrac%7B5%7D%7B5%7D%3D1)
We get the point (3,1).
Set x =8 and substitute in the given equation.
![y=\frac{8+2}{5}=\frac{10}{5}=2](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B8%2B2%7D%7B5%7D%3D%5Cfrac%7B10%7D%7B5%7D%3D2)
We get the point (8,2).
Mark the points (3,1) and (8,2) in the graph and join them by ray.
it is not possible to draw a vertical line to touch the graph of a function in more than one place. Since it is a line.
Recall that If it is not possible to draw a vertical line to touch the graph of a function in more than one place, then y is a function of x.
The given relation is a function.
The answer for A) is Yes.
Recall that the domain of a graph consists of all the input values shown on the x-axis.
The line has no end on both sides,
For all real values, the function is valid.
The answer for B is