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Bad White [126]
3 years ago
10

Someone answered before but I couldn’t get the link he posted anyone else know?

Mathematics
1 answer:
Scrat [10]3 years ago
7 0

Answer:

What exactly is your question?

Step-by-step explanation:

You might be interested in
One bag of rice that weighs 4.5 pounds will have enough rice if a recipe calls for 60 ounces of rice. (1 pound = 16 ounces)
dimulka [17.4K]

Answer:

Step-by-step explanation:

Since the bag of rice is 4.5 pounds, and there are 16 ounces per pound, multiply 16 x 4 = 64. Now what is half of 16? 8! So divide 5/8 = 0.625.

So in the end, yes the bag of rice will have enough rice. Here's my math:

16 x 4 = 64

5 / 8 = 0.625

So, you will have 64.625 ounces of rice which is plenty for your recipe!

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I really hope this helps you!

6 0
3 years ago
you better container of cat litter for 13.75 and a bag of cat food for x amount of dollars the total purchase is $20.80 which in
fenix001 [56]

I think its $6.22 for cat food

7 0
3 years ago
TJ earns a 20% commission on all sales plus a base salary of $40,000. His total income last year was more than $70,000. Which in
sukhopar [10]

Answer:

40,000 + 0.2x ≥ 70,000


3 0
3 years ago
Solve this for x. I have had 3 tries and can’t get the right answer.
Tanya [424]
Let's do both. For the first one, we can add 1 to both sides using the property of equality, and get 4x < -12. Then, we divide by 4, getting us x<-3. For the second, we subtract 3 from both sides to get -2x < 4. Then, we divide by -2 on both sides, but when we divide by a negative we have to switch the sign. So, we get x > -2. Hope this helps.
4 0
4 years ago
Read 2 more answers
(x+2)^2+(x-3)^2-2x^2)
garri49 [273]

Answer:

<u>13 - 2x </u>

Step-by-step explanation:

(x +2)² + (x - 3)² - 2x²

<em>Expand.</em>

(x + 2)(x + 2) + (x - 3)(x - 3) - 2x²

x² + 2x + 2x + 4 + x² - 3x - 3x + 9 - 2x²

<em>Bring all the like terms together then simply.</em>

x² + x² - 2x² + 2x + 2x - 3x - 3x + 4 + 9

2x² - 2x² + 4x - 6x + 13

= <u>13 - 2x</u> (or <u>-2x + 13</u> )

4 0
3 years ago
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