we can use MS excel to plot the given data and check whether the graph's trendline has an R-squared of 1. The graph does not fit into a line but fits into an exponential function. The trendline's equation is equal to y = 4e^1.3863x where R squared is equal to 1
Te x intercepts are where the graph crosses the x axis or wher y=0
the y intercept is where the graph crosses the y axis or where x=0
to find vertex, here is a hack
the x coordinate of the vertex for an equation in form ax^b+bx+c=y is -b/2a
so
y=3x^2+12x+7
-b/2a=-12/2(3)=-12/6=-2
sub that back
y=3(-2)^2+12(-2)+7
y=3(3)-24+7
y=9-17
y=-8
vertex is (-2,-8)
intercepts
x intercept is where y=0
0=3x^2+12x+7
using quadratic formula
x=(-6-√15)/3 and (-6+√15)/3
xints at ((-6-√15)/3,0) and ((-6+√15)/3,0)
yint is where x=0
set x=0
y=7
yint is at y=7 or (0,7)
vertex at (-2,-8)
xints at x=

and

or at the points

and

yint at y=7 or at (7,0)
Answer:
6
Step-by-step explanation:
3( 4x - 6)
Let x =2
3( 4*2 -6)
3(8-6)
3*2
6
Check
12x-18
12*2 -18
24-18
6
Both equal 6
progress prior to 1980. if n is an integer greater than two (n > 2)