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Sum of n terms = a1 (r^n-1/ (r-1)
Sum of first one = 3 * (4^5 - 1) / 3 = 1023
.. 2nd = 5 * (6^2 - 1) / 5 = 35
.. 3rd = 5 ^4 - 1 / 4 = 156
.. 4th = 4 * (5^4 - 1) / 4 = 624
So in increasing order its 2nd, 3rd, 4th and first.
The formula would be I=(37)(.04)(6) which would give you $8.88
Answer:
4
Step-by-step explanation:
Using the rule of radicals
×
⇔ 
Given

= 
=
× 
= 2
The widest are the ones with smallest fraction so the answer is C.