There are two ways to do this but the way I prefer is to make one of the equations in terms of one variable and then 'plug this in' to the second equation. I will demonstrate
Look at equation 1,

this can quite easily be manipulated to show

.
Then because there is a y in the second equation (and both equations are simultaneous) we can 'plug in' our new equation where y is in the second one

which can then be solved for x since there is only one variable

and then with our x solution we can work out our y solution by using the equation we manipulated

.
So the solution to these equations is x=-2 when y=6
Answer:
See explanation
Step-by-step explanation:
Hello, we cannot see the ellipse equations.
The eccentric of an ellipse is given by:

Assuming the equations are:

Then a²=25 and b²=16




The eccentricity is:

If the ellipse has equation,

then the this time, we have a=5 and b=3.
This means that:





Answer:
(x-10)(x+10)
Step-by-step explanation:
x^2 – 100
This is the difference of squares
x^2 - 10^2
We know that (a^2 - b^2) = (a-b) (a+b)
(x-10)(x+10)
Note that when rounding, if the number is:
5 or greater, round up
4 or less, round down
43.68532 rounded to the nearest dollar is 44, as 6 rounds up
$44 is your answer
hope this helps