sin(3)+cos(3)sin(3)tan(3)3=0=−cos(3)=−1=−4+,∈ℤ=−12+3
sin(3x)+cos(3x) =0 sin(3x) =−cos(3x) tan(3x) =−1 3x =−
π
4
+kπ,k∈
Z
x =−
π
12
+
k
π
3
Since −<<
−
π
<
x
<
π
, −2≤≤3
−
2
≤
k
≤
3
. Thus, the solution set is
{−34,−512,−12,4,712,1112}
The answer is B hope it helped you
Set the two "y='s" to each other and then solve for x.
To start it off you would do this: 6x-2=-6x+6
Then you would isolate x and get your answer.
Hi.
An example of a fraction equivalence chain is this:

You can keep multiplying

by 2 to get a fraction chain.
Hope this helps!
Step-by-step explanation:
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