9514 1404 393
Answer:
- 128°
- 52°
- 47°
- 133°
- 81°
Step-by-step explanation:
Alternate interior angles are congruent, so you know ...
∠2 = 52°
∠3 = 47°
The sum of angles in a triangle is 180°, so ...
∠5 = 180° -∠2 -∠3 = 180° -52° -47°
∠5 = 81°
Linear pairs are supplementary, so ...
∠1 = 180° -∠2 = 180° -52°
∠1 = 128°
∠4 = 180° -∠3 = 180° -47°
∠4 = 133°
_____
<em>Alternate solution</em>
To find angles 1 and 4, you could also make use of the fact that same-side interior angles are supplementary.
Hi! I believe the answers are:
1. c
2. h
3. b
4. f
5. d
6. g
7. a
8. e
this is kinda my best guess though so make sure to double check before using these.
Hope this helps :)
There are no shaded regions below so we cannot find the value of these things
Answer:
see explanation
Step-by-step explanation:
Assuming you require the derivative of f(x) from first principles, then
f' (x) =
![\frac{f(x+h)-f(x)}{h}](https://tex.z-dn.net/?f=%5Cfrac%7Bf%28x%2Bh%29-f%28x%29%7D%7Bh%7D)
=
![\frac{\frac{1}{(x+h)}-\frac{1}{x} }{h}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7B1%7D%7B%28x%2Bh%29%7D-%5Cfrac%7B1%7D%7Bx%7D%20%20%7D%7Bh%7D)
=
![\frac{\frac{x-(x+h)}{x(x+h)} }{h}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7Bx-%28x%2Bh%29%7D%7Bx%28x%2Bh%29%7D%20%7D%7Bh%7D)
=
![\frac{\frac{x-x-h}{x(x+h)} }{h}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7Bx-x-h%7D%7Bx%28x%2Bh%29%7D%20%7D%7Bh%7D)
=
← cancel h on numerator/ denominator
= -