In ΔOPQ, o = 6.6 inches, p = 2.1 inches and q=6 inches. Find the measure of ∠O to the nearest 10th of a degree.
1 answer:
Answer:
The measure of ∠O is 97.2° to the nearest tenth
Step-by-step explanation:
To solve this question, we will use the cosine rule
In Δ OPQ
Side o is opposite to ∠O
Side p is opposite to ∠P
Side q is opposite to ∠Q
By using the cosine rule
∵ o² = p² + q² - 2(p)(q)cos∠O
∵ o = 6.6 inches
∵ p = 2.1 inches
∵ q = 6 inches
→ Substitute them in the rule above
∴ (6.6)² = (2.1)² + (6)² - 2(2.1)(6)cos∠O
∴ 43.56 = 4.41 + 36 - 25.2cos∠O
→ Add the like terms in the right side
∴ 43.56 = 40.41 - 25.2cos∠O
→ Subtract 40.41 from both sides
∵ 3.15 = -25.2cos∠O
→ Divide both sides by -25.2 to find cos∠O
∴ -0.125 = cos∠O
→ Use your calculator to find ∠O
∵ m∠O =
∴ m∠O = 97.18075578
→ Round it to the nearest tenth ⇒ 2d.p.
∴ m∠O = 97.2°
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