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2 years ago

Using as much of the new vocabulary describe what you see in the diagram below

Mathematics

1 answer:

Arlecino [84]2 years ago

8 0

The photo's blurry luv, we can't see it

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Can someone please help me with these what are the answers?

cupoosta [38]

Answer:

1. A relation

2b. Continuous

Step-by-step explanation:

1: A relation is any set of ordered pairs. A function is a set of ordered pairs where there is only one value for every value.

2b: Continuous if the values belonging to the set can take on ANY value within a finite or infinite interval. A set of data is discrete if the values belonging to the set are distinct and separated.

4 0

2 years ago

Express 80 as the product of its prime factors. Write the prime factors in ascending order.

stepan [7]

Answer:

the answer of that is 16 x 5

Step-by-step explanation:

7 0

1 year ago

Explain how to subtract 247 from 538

forsale [732]

538
-247
------
8-7=1
Cross out 5 and make it 4. Make 3 into 13. 13-4=9
4-2=2

The answer is: 291

4 0

2 years ago

D 1. Given the number 47,135,280, what is the place value of the number "1"?

Anit [1.1K]

Answer:

one Hundred Thousand

Step-by-step explanation:

4 0

2 years ago

Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B rounds every 1 minute and 40 seconds in the gate 2. I

Elden [556K]

Answer:

$Time = 11\frac{2}{3}\ min$

Step-by-step explanation:

Given

$Security\ A = 2\ mins, 20\ secs$

$Security\ B = 1\ mins, 40\ secs$

Required

After how many minutes, will they round together

First, convert the given time to minutes

$Security\ A = 2\ mins, 20\ secs$

$Security\ A = 2\ mins+ 20\ secs$

$Security\ A = 2\ mins+ \frac{20}{60}\ min$

$Security\ A = 2\ mins+ \frac{1}{3}\ min$

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\ mins, 40\ secs$

$Security\ B = 1\ mins+ 40\ secs$

$Security\ B = 1\ mins+ \frac{40}{60}\ min$

$Security\ B = 1\frac{2}{3}\ min$

So, we have:

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\frac{2}{3}\ min$

List out the multiples of the time of both security personnel take round.

$Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...$

$Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...$

In the above lists, the common time is:

$Time = 11\frac{2}{3}\ min$

This implies that they go on round after $11\frac{2}{3}\ min$

4 0

2 years ago