(4y − 3)(2y2 + 3y − 5)

Mathematics

1 answer:

IRINA_888 [86]3 years ago

6 0

Answer:

$8y^3 + 6y^2- 29y + 15$

Step-by-step explanation:

$(4y-3)(2y^2+3y-5)\\4y(2y^2 + 3y - 5) - 3(2y^2+3y-5)\\8y^3+12y^2-20y-3(2y^2+3y-5)\\8y^3+12y^2-20y-6y^2-9y+15\\8y^3+6y^2-29y-9y+15\\= 8y^3+6y^2-29y+15$

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