Answer:
A - The can was open and gases were released.
Answer:
Explanation:
The charges are as follows:
since oxidation number of lead is 2 as indicated lead (II)nitrite. The number in parentheses indicates the oxidation number.
bears the charge -1.
As lead bears 2 positive charges so we need two nitrite ions to form lead (II) nitrite.
, it is a halogen and bears the charge -1.
, it is an alkali metal.
Since Bromide bears -1 charge and potassium bears +1 charge so we need only 1 ion of bromide and 1 ion of potassium to form potassium bromide.
Similarly, to form lead bromide we need 2 ions of bromide and 1 ion of lead, and to form potassium nitrite we need 1 nitrite ion and 1 potassium ion.
The final balanced equation is as follows, the various states of reactants and products are also written properly.
Answer: option D. Response to environment.
Justification:
Organisms respond to their environment in a variety of ways.
The environment interacts with the organisms via stimulus and the response to such stimulus is named tropism.
The example of the question, the plant's stem bends toward the window, is called positive phototropism, which means that the plant growth response to light such that the stems bend toward light to permit the leaves to receive more light.
The plant's stems posses positive phototropism and negative gravitropism.
Gravitropism is the response of the plant growth to gravity.
Stems grow away from gravity meaning that this is negative gravitropism, but roots grow toward gravity which is positive gravitropism.
Your distance would be greater than your displacement.
Concentration (m) signify 'molality'
Concentration (M) signify 'Molarity'
Formula for molality (m) =
In the question denisty of solute is not given so we can calculate concentration (M) that is 'Molarity'
Molarity (M) =
Moles of solute CH3OH = Given grams / Molar mass of CH3OH
Given grams of CH3OH = 12.9 g and molar mass = 32.0 g/mol
Moles of solute CH3OH =
Moles of solute CH3OH = 0.403 mol
Volume of solution = 230 mL , we need to convert 230 mL to 'L'
Volume =
Volume = 0.23 L
Molarity (M) =
Concentration (M) = 1.75 mol / L or 1.75 M