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3 years ago

I need help please help me !

Chemistry

1 answer:

kirill [66]3 years ago

3 0

Answer:

the rust formed because of the water sitting in sied a metal bowl for long time but they can fix this if they get filters

Explanation:

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Which product forms from a reaction between calcium (Ca) and phosphorus

IrinaVladis [17]

Answer:

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2 years ago

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Describe the theory of ionization in regard to acids and bases

dmitriy555 [2]

Acids are substances which produce hydrogen ions in solution.Bases are substances which produce hydroxide ions in solution.

7 0

3 years ago

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Nickel and carbon monoxide react to form nickel carbonyl, like this: (s)(g)(g) At a certain temperature, a chemist finds that a

horsena [70]

The question is incomplete, here is the complete question:

Nickel and carbon monoxide react to form nickel carbonyl, like this:

$Ni(s)+4CO(g)\rightarrow Ni(CO)_4(g)$

At a certain temperature, a chemist finds that a 2.6 L reaction vessel containing a mixture of nickel, carbon monoxide, and nickel carbonyl at equilibrium has the following composition:

Compound Amount

Ni 12.7 g

CO 1.98 g

$Ni(CO)_4$ 0.597 g

Calculate the value of the equilibrium constant.

Answer: The value of equilibrium constant for the reaction is 2448.1

Explanation:

We are given:

Mass of nickel = 12.7 g

Mass of CO = 1.98 g

Mass of $Ni(CO)_4$ = 0.597 g

Volume of container = 2.6 L

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Given mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

$\text{Equilibrium concentration of nickel}=\frac{12.7}{58.7\times 2.6}=0.083M$

$\text{Equilibrium concentration of CO}=\frac{1.98}{28\times 2.6}=0.0272M$

$\text{Equilibrium concentration of }Ni(CO)_4=\frac{0.597}{170.73\times 2.6}=0.00134M$

For the given chemical reaction:

$Ni(s)+4CO(g)\rightarrow Ni(CO)_4(g)$

The expression of equilibrium constant for the reaction:

$K_{eq}=\frac{[Ni(CO)_4]}{[CO]^4}$

Concentrations of pure solids and pure liquids are taken as 1 in equilibrium constant expression.

Putting values in above expression, we get:

$K_{eq}=\frac{0.00134}{(0.0272)^4}\\\\K_{eq}=2448.1$

Hence, the value of equilibrium constant for the reaction is 2448.1

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3 years ago

How much oxygen in NaO2

Yuri [45]

Answer:

there is only 2 oxygen's in NaO2

Explanation:

Na O2

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3 years ago

A sample contains sulfur-32 and sulfur-36. If the average mass is 33 amu what is the abundance of sulfur 32?

mrs_skeptik [129]

32*x + (1-x) * 36 =33
32x _36-36x =33
-4x = -3
x=.75
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6 0

3 years ago