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2 years ago

If Anna can run 2km in 8 min, how long will it take her to run 5 km if she maintains her speed

Mathematics

1 answer:

rodikova [14]2 years ago

5 0

Answer:

20 minutes

Step-by-step explanation:

Find the speed per km. 2km/8min. This is 4 minutes per km.

Next, multiply the minutes per km by km. 4 min x 5 km.

This equals 20 :)

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A farmer has 300 ft of fence to enclose 2 adjacent rectangular pens bordering his barn. Find the maximum area he can close.

Margarita [4]

Answer:

Width of 37.5 feet and length of 50 feet will maximize the area.

Step-by-step explanation:

Let w represent width and l represent length of the pen.

We have been given that a farmer has 300 ft of fence to enclose 2 adjacent rectangular pens bordering his barn. We are asked to find the dimensions that will maximize the area.

We can see from the attachment that the perimeter of the pens would be $4w+3l$ .

We can set our given information in an equation $4w+3l=300$ .

The area of the two pens would be $A=2l\cdot w$ .

From perimeter equation, we will get:

$w=\frac{300-3l}{4}$

Substituting this value in area equation, we will get:

$A=2l\cdot (\frac{300-3l}{4})$

Since we need to maximize area, so we need to find derivative of area function as:

$A=\frac{600l-6l^2}{4}$

Bring out the constant:

$A=\frac{1}{4}*\frac{d}{dl}(600l-6l^2)$

$A=\frac{1}{4}*(600-12l)$

$A=150-3l$

Now, we will set our derivative equal to 0 as:

$150-3l=0$

$150=3l$

$\frac{150}{3}=\frac{3l}{3}$

$50=l$

Now, we will substitute $l=50$ in equation $w=\frac{300-3l}{4}$ to solve for width as:

$w=\frac{300-3(50)}{4}$

$w=\frac{300-150}{4}$

$w=\frac{150}{4}$

$w=37.5$

Therefore, width of 37.5 feet and length of 50 feet will maximize the area.

8 0

3 years ago

Eric plays basketball and volleyball for a total of 95 minutes every day. He plays basketball for 25 minutes longer than he play

ioda

Answer:

Part A:

x+y= 95

x = y+25

Part B : 35 minutes

Part C : No

Step-by-step explanation:

Part A :

Eric plays basketball and volleyball for a total of 95 minutes every day

x+y= 95

Where:

x =the number of minutes Eric plays basketball

y= the number of minutes he plays volleyball

He plays basketball for 25 minutes longer than he plays volleyball.

x = y+25

System:

x+y= 95

x = y+25

Part B:

Replacing x=y+25 on the first equation:

(y+25) + y =95

Solving for Y

y+25+y =95

25+2y=95

2y=95-25

2y=70

y = 70/2

y = 35 minutes

Part C : No

if x = 35

x+y= 95

35+y =95

y= 95-35

y = 60 minutes

Replacing y=60 on the other equation:

x = y+25

35 = 60+25

35 ≠85

5 0

3 years ago

WAaAa im very confused, help

algol [13]

Answer:

The answer would be 3.2, since .2 is equivalent to 1/5 ^^

7 0

2 years ago

Read 2 more answers

Select the simplification that accurately explains the following statement.

Mariana [72]

<u>Answer</u>

<u>Explanation</u>

9⁽¹/²⁾² = (9⁽¹/²⁾)²

= 9¹/² × 9¹/² (Since the base are the same, we can add the power.)

= 9⁽¹/² ⁺¹/²⁾

= 9 ¹

= 9

The correct simplification is D.

8 0

3 years ago

Kayla’s dollhouse has 15.15 square feet downstairs and 6.45 square feet upstairs. What is the estimated total area if you round

Hitman42 [59]

The area of Kayla's dollhouse upstairs = 15.15 square feet

The area of Kayla's dollhouse downstairs = 6.45 square feet

To find the estimated Total area of Kayla's dollhouse, we would apply the Addition Operation

The estimated total area is calculated using the formula :

Area of the dollhouse upstairs + Area of the dollhouse downstairs

Rounding to the decimals to the nearest tenth

The area of Kayla's dollhouse upstairs to the nearest tenth = 15.2 square feet

The area of Kayla's dollhouse downstairs to the nearest tenth = 6.5 square feet

15.2 square feet + 6.5 square feet = 21.7 square feet

The estimated total area of Kayla's dollhouse is 21.7 square feet

To learn more, visit the link below:

brainly.com/question/11118181

8 0

3 years ago

If Anna can run 2km in 8 min, how long will it take her to run 5 km if she maintains her speed​

If Anna can run 2km in 8 min, how long will it take her to run 5 km if she maintains her speed