Find the series in A.P whose sum to n terms is n*(n+2)
1 answer:
Answer:
3, 5, 7, 9, 11, .........
Step-by-step explanation:
Given
= n(n + 2) , then
S₁ = 1(1 + 2) = 1(3) = 3 ⇒ a₁ = 3
S₂ = 2(2 + 2) = 2(4) = 8
S₃ = 3(3 + 2) = 3(5) = 15
Thus
a₂ = S₂ - S₁ = 8 - 3 = 5
a₃ = S₃ - S₂ = 15 - 8 = 7
The first 3 terms are 3, 5, 7
This is an AP with common difference d = 2, then
a₄ = a₃ + 2 = 7 + 2 = 9
a₅ = a₄ + 2 = 9 + 2 = 11
and so on
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Answer:
In step 1 subtraction property is used and in step 2 division property is used.
Explanation:
We have the equation 2x + 6 = 22
Step 1
The subtraction property of equality tells us that subtracting the same number to each side of an equation gives us an equivalent equation
So subtracting 6 from both sides
2x + 6 - 6 = 22 - 6
2x = 16
Step 2
The division property of equality tells us that you can divide each side of an equation with the same nonzero number to produce an equivalent equation
So dividing each side by 2.