Question

Given square ABCD, with point P on side AB , point Q on side BC, point R on side CD, and point S on side DA as shown. Additionally, P is 2/3 of the way from A to B, Q is 2/3 of the way from B to C, R is 2/3 of the way from C to D, and S is 2/3 of the way from D to A. Compute the ratio of the area of square PQRS to the area of square ABCD. Write your answer as a fraction in lowest terms.

Answer 1

The ratio of the area of square PQRS to the area of square ABCD is 5/9

Area of square ABCD

Assume the measure of the side lengths of the square ABCD is 1, then the area of the square ABCD is:

$A_1 = 1 \times 1$

$A_1 = 1$

See attachment for the diagram that represents the relationship between both squares.

Pythagoras theorem

The measure of length PQ is then calculated using the following Pythagoras theorem:

$PQ^2 = (\frac 13)^2 + (\frac 23)^2$

Evaluate the squares

$PQ^2 =\frac 19 + \frac 49$

Add the fractions

$PQ^2 =\frac 59$

Area of square PQRS

The above represents the area of the square PQRS.

i.e.

$A_2 =\frac 59$

So, the ratio of the area of PQRS to ABCD is:

$Ratio = \frac{A_2}{A_1}$

This gives

$Ratio = \frac{5/9}{1}$

$Ratio = \frac{5}{9}$

Hence, the ratio of the area of square PQRS to the area of square ABCD is 5/9

Read more about areas at:

brainly.com/question/813881