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Kipish [7]
3 years ago
7

If the radius of a cone is 2 and the height is 4 what is the volume

Mathematics
1 answer:
laila [671]3 years ago
4 0
Your answer: V≈16.76
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A is the midpoint (3,6) and B is the midpoint (11,12).find the coordinates of midpoint of AB
tamaranim1 [39]

Answer:

X, y first column ++

Second column +-

Fourth column - -

Fiveth column _+

6 0
4 years ago
Read 2 more answers
I really need help here ASAP​
AlexFokin [52]

Answer:

D. x=\frac{-4-\sqrt{31}}{3} or  x=\frac{-4+\sqrt{31}}{3}

Step-by-step explanation:

The given equation is:

3x^2+8x=5

Divide through by 3;

x^2+\frac{8}{3}x=\frac{5}{3}

Add the square of half the coefficient of x to both sides.

x^2+\frac{8}{3}x+(\frac{4}{3})^2=\frac{5}{3}++(\frac{4}{3})^2

x^2+\frac{8}{3}x+\frac{16}{9}=\frac{5}{3}+\frac{16}{9}

The left hand side is now a perfect square:

(x+\frac{4}{3})^2=\frac{31}{9}

Take square root

x+\frac{4}{3}=\pm \sqrt{ \frac{31}{9}}

x=-\frac{4}{3}\pm \sqrt{ \frac{31}{9}}

x=-\frac{4}{3}\pm \frac{\sqrt{31}}{3}

D. x=\frac{-4-\sqrt{31}}{3} or  x=\frac{-4+\sqrt{31}}{3}

5 0
3 years ago
Two consecutive positive integers have a
Ierofanga [76]
7 times 8 = 56 and both are consecutive numbers
6 0
3 years ago
Please help me it’s due today
Alchen [17]

Answer:

Northside

Median: 36

Range: 32

IQR: 17

Southside:

Median: 39

Range: 38

IQR: 22

Step-by-step explanation:

Northside first

Order the ages from least to greatest

24, 28, 32, 32, 32, 36, 41, 44, 49, 49, 56

Median is 36 since it's in the middle

Subtract the greatest number from the smallest number to find the range (56-24) = 32

To find the IQR you need the ages least to greatest

24, 28, 32, 32, 32, 36, 41, 44, 49, 49, 56

Find the lower quarter = 32

Find the upper quarter = 49

Subtract 49 and 32 (49-32) = 17

Southside

The Median is the line at the middle of the box, in this case its between 38 and 40 which is 39.

The range is 61 - 23 = 38 (Greatest - least)

The IQR is 52 - 30 = 22

Hope this helps!

7 0
2 years ago
Read 2 more answers
SOMEONE HELP‼️THE WORK IS FINISHED ONT THAT SIDE BUT HELP ON THE OTHER SIDE ‼️
Amanda [17]

Answer:

e) Shamika= 224 balloon, Crystal= 112 balloon, Aliya= 114 Balloon.

f)  We know,Crystal sold "b" balloon

           Aliya sold (b+2) balloon

          Shamika sold 2b balloon.

As per data given in question part c that each balloon cost $2 and Total cost of balloon is $900.

Now, solving to find how much each student sold balloon at school´s winter dance.

As we know total cost is $900 and each balloon cost is $2.

∴ Total cost= Total\ quantity \times cost\ of\ each\ unit

Total quantity= {b+(2+b)+2b}

∴ \$ 900= {b+(2+b)+2b}\times \$ 2

Once we solve, we will get the value of b as 112 balloon, which is the number of balloon sold by Crystal.

Substituting the value of b in the equation of Aliya and Shamika, we will get the number of balloon sold by them.

Which is 114 and 224 respectively.

Step-by-step explanation:

Given: Crystal sold "b" balloon

           Aliya sold (b+2) balloon

          Shamika sold 2b balloon.

As per data given in question part c that each balloon cost $2 and Total cost of balloon is $900.

Now, solving to find how much each student sold balloon at school´s winter dance.

As we know total cost is $900 and each balloon cost is $2.

∴ Total cost= Total\ quantity \times cost\ of\ each\ unit

Total quantity= {b+(2+b)+2b}

∴ \$ 900= {b+(2+b)+2b}\times \$ 2

Opening the parenthesis.

⇒\$ 900= (b+2+b+2b)\times \$ 2

⇒\$ 900= 2+4b \times 2

Dividing both side by 2

⇒ \$ 450= 2+4b

Subtracting both side by 2

⇒ \$ 448= 4b

Cross multiplying

∴b= \frac{448}{4} = 112

∴ b= 112.

Hence, we can say Crystal have sold 112 balloons.

Next subtituting the  value of "b" in the equation for Aliya and Shamika to get number of balloon they have sold.

We know, Aliya sold b+2 balloons

∴ Aliya sold= 112+2= 114\ balloon

Aliya sold 114 balloon.

We know, Shamika sold 2b balloons

∴2\times 112= 224 balloon.

Shamika sold 224 balloon.

7 0
3 years ago
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