Question

Solve the equation by factoring: 12y^3 – 13y^2 + 3y = 0

Answer 1

Answer:

y = 0, y = $\frac{1}{3}$, y = $\frac{3}{4}$

Step-by-step explanation:

Given

12y³ - 13y² + 3y = 0 ← factor out y from each term

y(12y² - 13y + 3) = 0

y(3y - 1)(4y - 3) = 0 ← in factored form

Equate each factor to zero and solve for y

y = 0

3y - 1 = 0 ⇒ 3y = 1 ⇒ y = $\frac{1}{3}$

4y - 3 = 0 ⇒ 4y = 3 ⇒ y = $\frac{3}{4}$