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bazaltina [42]
4 years ago
15

The sum of 2 numbers us 19 and their didfference is 55 what are the two numbers

Mathematics
1 answer:
damaskus [11]4 years ago
4 0
Let one no. be x.
then another no. = (19-x).
x - (19 - x ) = 55
2 x - 19 = 55
x = 37
another no. = 19 - 37 = -18

Can you follow me and like me please? I hope i can help you more.☺
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A circle has a diameter of 6 meters. Which statement about the circumference and area is true?
worty [1.4K]

Answer:

The numerical value of the circumference is greater than the numerical value of the area.

Step-by-step explanation:

This has already been answered

8 0
3 years ago
Read 2 more answers
HELPP
algol13
I am assuming the both cylinders have the same measure of radius. They only differ in height.

Larger Cylinder = 343 ft³
Smaller Cylinder = 125 ft³ ; height = 5 ft.

We can use proportion for this problem; a:b = c:d where ad = bc

5 ft :125 ft³ = x : 343ft³
5 ft * 343 ft³ = 125 ft³ * x
1715 ft⁴ = 125 ft³ * x
1715 ft⁴ ÷ 125 ft³ = x
13.72 ft = x  height of the larger cylinder.

Cone S = 768pi cm³
Cone T = 6144pi cm³ ; height = 24 cm

24 cm : 6144 cm³ = x : 768 cm³
24 cm * 768 cm³ = 6144 cm³ * x
18,432 cm⁴ = 6144 cm³ * x 
18,432 cm⁴ ÷ 6,144 cm³ = x
3 cm = x height of Cone S.



6 0
3 years ago
A. 56.32 B. 40 C. 96.52 D. 143.62
Ivahew [28]

Answer:d

Step-by-step explanation:

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3 years ago
Factor completely 2x^3+4x^2+6x+12
PilotLPTM [1.2K]

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Step-by-step explanation:

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Four batsmen on a cricket team had a mean of 42.5 runs the other 7 batsmen had a mea of 18 what was the mean number of scored by
Ira Lisetskai [31]

Answer:

The mean score of the entire team is 26.909.

Step-by-step explanation:

Given that four batsmen had a mean of 42.5.

Let $ \textbf{B}_{\textbf{i} $, where $ i = 1, 2, 3, \hdots, 11 $ denote the batsmen.

From the first statement, we have:

$ \frac{B_1 + B_2 + B_3 + B_4}{4} = 42.5 $

$ \implies B_1 + B_2 + B_3 + B_4 = 42.5 \times 4 =  \textbf{170} $

Therefore, the sum of the scores of the first four batsmen is 170.

Now, from the second statement we have:

$ \frac{B_5 + B_6 + B_7 + B_8 + B_9 + B_{10} + B_{11}}{7} = 18 $

$ \implies B_5 + B_6 + B_7 + B_8 + B_9 + B_{10} + B_{11} = 18 \times 7 = \textbf{126} $

That is, the sum of the scores of the remaining 7 batsmen is 126.

Now, to calculate the average(mean) of the entire team, we add the individual scores and divide it by 11.

$ \implies \frac{B_1 + B_2 + B_3 + B_4 + B_5 + B_6 + B_7 + B_8 + B_9 + B_{10} + B_{11}}{11} = \frac{170 + 126}{11} $

$ = \frac{296}{11} $

$ = \textbf{26.90} $ which is the required answer.

8 0
3 years ago
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