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2 years ago

Are these fractions equivalent or nonequivalent? 4/9 8/18

Mathematics

2 answers:

aleksklad [387]2 years ago

7 0

Yes, these are equivalent

LuckyWell [14K]2 years ago

5 0

4/9 and 8/18 are equivalent fractions. We can also verify equivalent fractions by reducing them to their lowest terms. 2.

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The time to assemble the first unit on a production line is 8 hours. The learning rate is 0.81. Approximately how long will it t

pochemuha

Answer:

4.428 hours

Step-by-step explanation:

If the learning rate is 0.81, the slope of the learning curve is:

$b=\frac{ln(0.81)}{ln(2)} \\b=-0.304$

The time it takes to produce the n-th unit is:

$T_n=T_1*n^b$

If T1 = 8 hours, the time required to produce the seventh unit will be:

$T_n=8*7^{-0.304}\\T_n=4.428\ hours$

It will take roughly 4.428 hours.

3 0

3 years ago

If log a = x and log b = y, then log (ab2) equals

mylen [45]

Answer:

The answer for log(ab²) is x + 2y.

Step-by-step explanation:

You have to apply Logarithm Law,

$log(a) + log(b) \: ⇒ \: log(a \times b)$

$log( {a}^{n} ) \: ⇒ \: n log(a)$

In this question, you have to seperate it out :

$log(a {b}^{2} ) = log(a) + log( {b}^{2} )$

$log( {b}^{2} ) = 2 log(b)$

$let \: log(a) = x$

$let log(b) = y$

$log(a {b}^{2} ) = log(a) + 2 log(b)$

$log(a {b}^{2} ) = x + 2y$

3 0

3 years ago

You drive 45 miles per hour. what is your speed in feet per second

Oxana [17]

You can use a calculator online.
Here's the link but I already did it for you

https://www.metric-conversions.org/speed/miles-per-hour-to-feet-per-second.htm?val=45

It's 66 ft per second.

7 0

3 years ago

Will mark brainliest

lubasha [3.4K]

1. V = r² π hV = 3² π · 10 = 90 π in³Answer: C.2. r = 18/2 = 9 yd, h = 3 ydV = 9² π · 3 = 243 π yd³3. r = 46.25 / 2 = 23.125 cmh = 18.5 cmV = 23.125² · 3.14 · 18.5 = 31,064.53 cm³4. h = 1934, d = 1934 · 125 = 241,750 , r = 241.750 / 2 = 120,875 V = 120,875² · 3.14 · 1934 = = 14,610,765,625 · 3.14 · 1934 = = 88,727,673,056,875

7 0

3 years ago

1. Consider the population model dP dt = 0.2P 1 − P 135 , where P(t) is the population at time t. (a) For what values of P is th

Kryger [21]

Answer:

$P = 0$ OR $P = 135$

$P > 0$ and $P < 135$

Generally the carrying capacity is can be defined as the highest amount of population and environment can support for an unlimited duration or time period

$P = 67.5$