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Olenka [21]
3 years ago
10

What does noncollinear

Mathematics
1 answer:
Anit [1.1K]3 years ago
3 0

9514 1404 393

Answer:

  not on the same line

Step-by-step explanation:

Any two distinct points define a line. Additional points may or may not be on that line. If they are on the line, they are collinear with other points on the same line.

Any point not on the line is noncollinear with the points that are on the line.

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He equation sin (40 degree) equals StartFraction b Over 20 EndFraction can be used to determine the length of line segment AC.
Alisiya [41]

Answer:

The value of b is 12.9 cm

The value of a is 15.3 cm

Step-by-step explanation:

see the attached figure to better understand the problem

<em>Find the value of b</em>

we know that

in the right triangle ABC

The function sine of angle of 40 degrees is equal to divide the opposite side to the angle of 40 degrees (AC) by the hypotenuse (AB)

so

sin(40\°)=AC/AB

Solve for AC

AC=(AB)sin(40\°)

substitute the given value

AC=(20)sin(40\°)

AC=12.9\ cm

therefore

The value of b is 12.9 cm

<em>Find the value of a</em>

we know that

in the right triangle ABC

The function cosine of angle of 40 degrees is equal to divide the adjacent side to the angle of 40 degrees (BC) by the hypotenuse (AB)

so

cos(40\°)=BC/AB

Solve for BC

BC=(AB)cos(40\°)

substitute the given value

BC=(20)cos(40\°)

BC=15.3\ cm

therefore

The value of a is 15.3 cm

3 0
3 years ago
Read 2 more answers
Aggh please help with this
docker41 [41]
Sure ill help you what you need help with
6 0
3 years ago
The product of a number and 7 less than the number is 260. Find the numbers.
Mariulka [41]

Answer: 20,-13

Step-by-step explanation:

We can rewrite the problem as an equation. This equation is x(x-7)=260 (x being the mystery number). We can simply this into x^2 -7x=260. We can then rewrite this as x^2 -7x -260=0. We need to find the roots of this quadratic, which are -13 and 20. You can find this by factoring the quadratic.

8 0
2 years ago
Will mark brainliest, I'm having some trouble (question in attachment)
Liono4ka [1.6K]

Answer: 45b^4/32

Step-by-step explanation: First multiply the two fractions

15b^3y(3b)/8y x 4

Multiply 3 by 15

45b^3yb/8y x 4

Raise b to power of 1

45(b^1b^3)y/8y x 4

Use power rule to combine exponents

45b^1+3 y/8y x 4

Simplify

45b^4y/32y

Cancel common factor of y

45b^4/32

4 0
3 years ago
Is questions 1,4,5,6 correct? If not how do I do them? And how do I do question 2?
My name is Ann [436]
Yes your answers 1 and 4-6 are correct. great job!

1 for question 6 we need to distribute the -3 (our outside value) to our values inside our parentheses by multiplication

-3 x 2x = -6x
-3 x -5 = 15

new equation: 8x + 1 - 6x + 15

2. now combine like terms

8x - 6x = 2x
1 + 15 = 16

so our new equation with combined like terms is: 2x + 16








6 0
3 years ago
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