Please help me it is timed and i am running outta time
1 answer:
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Answer:
<em>If statement(1) holds true, it is correct that </em><em> is an integer.</em>
<em>If statement(2) holds true, it is not necessarily correct that </em><em> is an integer.</em>
<em></em>
Step-by-step explanation:
Given two positive integers and
.
To check whether is an integer:
Condition (1):
Every factor of is also a factor of
.
Let us consider an example:
which is an integer.
Actually, in this situation is a factor of
.
Condition 2:
Every prime factor of <em>s</em> is also a prime factor of <em>r</em>.
(But the powers of prime factors need not be equal as we are not given the conditions related to powers of prime factors.)
Let
which is not an integer.
So, the answer is:
<em>If statement(1) holds true, it is correct that </em><em> is an integer.</em>
<em>If statement(2) holds true, it is not necessarily correct that </em><em> is an integer.</em>
<em></em>
Answer:
x = 5
Step-by-step explanation:
because the log is base 2 you can remove the log by raing 2 to the power of each side:
the 2 and log2 cancel leaving:
this means we can now solve through simple algebra: