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marusya05 [52]
3 years ago
9

I need your help on this question

Mathematics
2 answers:
Solnce55 [7]3 years ago
5 0

Answer:

c, cause yeah

egoroff_w [7]3 years ago
3 0

Answer:

C: a quadrilateral with exactly one pair of parallel sides

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Henry invested money into a bank account. Each year the money in the account earns 3% interest. After one year, the total amount
iris [78.8K]

Answer: £164. 85

Step-by-step explanation:

169.95/100 x 3/1

= 1.6995 x 3

Interest= 5, 0985

Therefore total investment a at 31st December

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= £50,815

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4 years ago
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The mean output of a certain type of amplifier is 102 watts with a standard deviation of 12 watts. If 63 amplifiers are sampled,
sammy [17]

Answer:

0.97547

Step-by-step explanation:

Given That:

Mean (m) = 102

Standard deviation (σ) = 12

Sample size (n) = 63

Probability that sample mean would differ from Population mean by less than 3.4 watts

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P(102 - 3.4 < Z < 102 + 3.4)

Using the Z formula :

Zscore = (x - m) / (σ/√n)

x = 102 - 3.4 = 98.6 ; x = 102 + 3.4 = 105.4

Z = (98.6 - 102) / (12/√63) = −2.248888

P(Z < - 2.2488) = 0.012263 (Z probability calculator)

Z = (105.4 - 102) / (12/√63) = 2.2488886

P(Z < 2.2488) = 0.98774 (Z probability calculator)

0.98774 - 0.012263 = 0.97547

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3 years ago
Helllppppp NOOWWW!!!!!!! <br> PLZ
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Answer:

See below.

Step-by-step explanation:

The answer is B. The two lines intersect at 21, meaning both towns have the same amount of snow at this time.

-hope it helps

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3 years ago
Write an equation of the line that passes through (2,−5) and is parallel to the line 2y=3x+10
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Step-by-step explanation:

Divide two on both sides to get rid of it and the make the equation in the form y = mx + c

\frac{2}{2} y = \frac{3}{2} x +  \frac{10}{2}

y = 3/2x + 5

since both lines are parallel they must have the same gradient which is 3/2

y = 3/2x + c

All you have to do now is to replace x and y with (2, -5) to find c

x = 2

y = -5

-5 = 3/2 × 2 + c

-5 = 3 + c

c = -5-3

c = -8

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3 years ago
Simplify the expression (3+8i) - (4+2i) pls show work!
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Subtract like terms:

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3 years ago
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