we can multiply the equation with the invers of that fraction
The first five terms of the recursively defined sequence are 6, 12, 48, 768, 196608
For given question,
We have been given the recursive formula of a sequence.

Also, the first term of the sequence is,
a1 = 6
Substitute k = 1 in given recursive formula.
⇒ 
⇒ a2 = 1/3 (6)²
⇒ a2 = (1/3) × 36
⇒ a2 = 12
Substitute k = 2 in given recursive formula.
⇒ 
⇒ a3 = (1/3) × (12)²
⇒ a3 = (1/3) × 144
⇒ a3 = 48
Substitute k = 3 in given recursive formula.
⇒ 
⇒ a4 = (1/3) × (48)²
⇒ a4 = (1/3) × 2304
⇒ a4 = 768
Substitute k = 4 in given recursive formula.
⇒ 
⇒ a5 = (1/3) × (768)²
⇒ a5 = (1/3) × 589824
⇒ a5 = 196608
Therefore, the first five terms of the recursively defined sequence are 6, 12, 48, 768, 196608
Learn more about the recursive formula of sequence here:
brainly.com/question/14457800
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Answer:
1) 13
2) 1
Step-by-step explanation:
1) you add the e amount of people that went to the store 3 and 5 times because those are all more than 2.
2) 1 has the lowest number on the amount of landings.
Answer:
A. f(x)=9x+4
Step-by-step explanation:
Function is f(x) =9x+4, because if x=1, then f(1)=9*1+4=9+4=13;
if x=5,then f(5)=9*5+4=45+4=49
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