Answer:
y'(t)=ky(t)(100-y(t))
Step-by-step explanation:
The rate of change of y(t) at any time is the derivative of y with respect to time y, y'(t)
If y(t) is the percent of the population advocating war at time t
then 100-y(t) is the percent of the population not advocating war
The product of the percentage of the population advocating war and the percentage not advocating war would be
y(t)(100-y(t))
If the rate of change of y(t) at any time is proportional to the product of the percentage of the population advocating war and the percentage not advocating war, then
y'(t)=ky(t)(100-y(t))
where <em>k is the constant of proportionality
</em>
Answer:
x = number of days
y = number of remaining photos saved to her camera roll.
Step-by-step explanation:
Hi, to answer this question we have to write an equation:
The number of pictures saved in the camera roll (2,500) minus the amount of photos that she deletes per day (50) multiplied by the number of days (x) must be equal to the number of photos remaining.
y =2,500- 50x
The variables are x and y.
Where x is the number of days and y is the number of remaining photos.
Feel free to ask for more if needed or if you did not understand something
which is similar to n:1 where 
<u>Step-by-step explanation:</u>
Here we have to Express in the form n:1 give n as a decimal 21:12 . Let's find out:
Given ratio as 21:12 . Let's convert it into n:1 , where n is decimal
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
{ dividing denominator & numerator by 4 }
⇒ 
⇒ 
⇒ which is similar to n:1 where
Answer:
x=-6
Step-by-step explanation:
