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RSB [31]
3 years ago
10

How many moles of oxygen is required to produce 2.8 moles of water?

Chemistry
1 answer:
goldenfox [79]3 years ago
8 0

Answer:

2.8 moles

Explanation:

The formula for water is H2O, so one mole of water contains two moles of hydrogen and one mole of oxygen.

Here, the ratio of water particles to oxygen particles is one to one.

Therefore, in 2.8 moles of water, there are 2.8 moles of oxygen.

Hence, 2.8 moles of oxygen are required to produce 2.8 moles of water.

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14 Electrons

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silver has an atomic mass of 107.868 amu. silver has two common isotopes. one of the isotopes has a mass of 106.906 amu and a re
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A. The abundance of the 2nd isotope is 48.119%

B. The mass of the 2nd isotope is 108.905 amu

Let the 1st isotope be A

Let the 2nd isotope be B

A. Determination of the abundance of the 2nd isotope

Abundance of isotope A = 51.881%.

<h3>Abundance of isotope B =? </h3>

Abundance of B = 100 – A

Abundance of B = 100 – 51.881

<h3>Abundance of B = 48.119%</h3>

B. Determination of the mass of the 2nd isotope

Atomic mass of silver = 107.868 amu.

Mass of 1st isotope (A) = 106.906 amu

Abundance of isotope A (A%) = 51.881%.

Abundance of isotope B (B%) = 48.119%

<h3>Mass of 2nd isotope (B) =? </h3>

atomic \: mass =  \frac{mass \: of \:A \times \:A\%}{100}  + \frac{mass \: of \:B \times \:B\%}{100} \\  \\ 107.868 = \frac{106.906\times \ \: 51.881}{100}  + \frac{mass \: of \:B \times \:48.119}{100} \\  \\ 107.868 = \: 55.464 + 0.48119 \times mass \: of \:B  \\  \\  collect \: like \: terms \\  \\ 0.48119 \times mass \: of \:B  = 107.868  - 55.464  \\  \\ divide \: both \: side \: by \: 0.48119 \\  \\ mass \: of \:B  = \frac{107.868  - 55.464 }{0.48119}  \\  \\ mass \: of \:B  =108.905 \: amu \\  \\

Therefore, the mass of the 2nd isotope is 108.905 amu

Learn more: brainly.com/question/7955048

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2 years ago
The stability of an isotope is based on its
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Option 4. ratio of electrons to protons

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Identify the functional groups present in each molecule.
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