How many moles of oxygen is required to produce 2.8 moles of water?
1 answer:
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Answer:
a) <u>1.740 g</u> of F- must be added to a cylindrical water reservoir
b) Grams of sodium fluoride, NaF, that contain this much fluoride:
3.84 g
Explanation:
Step 1. calculate the volume of the tank:
Volume of cylinder =
,
Here r = radius of the cylinder = d/2
h = depth = 21.80m
= 168 m
Volume =
2.Convert ppm to g/m3 and Solve for mass of F-
Because both ppm and g/m3 are same quantity .
mass of F- required = 1.740 g
3. Apply <u>mole concept </u>to calculate grams of sodium fluoride produced
mass of 1 mole of F2 = 38 g
mass of 1 mole of NaF = 42 g
(from periodic table calculate molar mass)
Here 1 mole of F2 produce = 2 mole of NaF
So,
38 g of F2 produce = 2 x 42 g of NaF
38 g of F2 produce = 84 g of NaF
1 g of F2 produce = 84/38 g of NaF
1.74 g F2 produce =
1.74 g F2 produce = 3.84 g of NaF
3.84 g of NaF is produced