Question

Given the exponential function ƒ(x) = 45(1⁄3)x, find ƒ(0) and ƒ(1).

Answer 1

Answer:

f(0)= 45

f(1)= 15

Step-by-step explanation:

$f(x)= 45(\frac{1}{3})^x$

We are give with exponential function

to find f(0) we plug in 0 for x

$f(x)= 45(\frac{1}{3})^x$

$f(0)= 45(\frac{1}{3})^0$

anything to exponent 0 is 1

so f(0)= 45

to find f(1) we plug in 1 for x

$f(x)= 45(\frac{1}{3})^x$

$f(1)= 45(\frac{1}{3})^1$

$f(1)= (\frac{45}{3})=15$

f(1)= 15

Answer 2

Answer for f(0) = 15
Answer for f(1) = 15