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docker41 [41]
2 years ago
12

A school sold tickets to a musical.

Mathematics
2 answers:
kicyunya [14]2 years ago
6 0

m=6.50t

6.50 per ticket so you multiply 6.50 by t. The money collected is the answer to the equation. Hope this helps!

Westkost [7]2 years ago
3 0
6.50 because the amount of money they are getting
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A 1000-liter (L) tank contains 500 L of water with a salt concentration of 10 g/L. Water with a salt concentration of 50 g/L flo
djverab [1.8K]

Answer:

a) y(t)=50000-49990e^{\frac{-2t}{25}}

b) 31690.7 g/L

Step-by-step explanation:

By definition, we have that the change rate of salt in the tank is \frac{dy}{dt}=R_{i}-R_{o}, where R_{i} is the rate of salt entering and R_{o} is the rate of salt going outside.

Then we have, R_{i}=80\frac{L}{min}*50\frac{g}{L}=4000\frac{g}{min}, and

R_{o}=40\frac{L}{min}*\frac{y}{500} \frac{g}{L}=\frac{2y}{25}\frac{g}{min}

So we obtain.  \frac{dy}{dt}=4000-\frac{2y}{25}, then

\frac{dy}{dt}+\frac{2y}{25}=4000, and using the integrating factor e^{\int {\frac{2}{25}} \, dt=e^{\frac{2t}{25}, therefore  (\frac{dy }{dt}+\frac{2y}{25}}=4000)e^{\frac{2t}{25}, we get   \frac{d}{dt}(y*e^{\frac{2t}{25}})= 4000 e^{\frac{2t}{25}, after integrating both sides y*e^{\frac{2t}{25}}= 50000 e^{\frac{2t}{25}}+C, therefore y(t)= 50000 +Ce^{\frac{-2t}{25}}, to find C we know that the tank initially contains a salt concentration of 10 g/L, that means the initial conditions y(0)=10, so 10= 50000+Ce^{\frac{-0*2}{25}}

10=50000+C\\C=10-50000=-49990

Finally we can write an expression for the amount of salt in the tank at any time t, it is y(t)=50000-49990e^{\frac{-2t}{25}}

b) The tank will overflow due Rin>Rout, at a rate of 80 L/min-40L/min=40L/min, due we have 500 L to overflow \frac{500L}{40L/min} =\frac{25}{2} min=t, so we can evualuate the expression of a) y(25/2)=50000-49990e^{\frac{-2}{25}\frac{25}{2}}=50000-49990e^{-1}=31690.7, is the salt concentration when the tank overflows

4 0
3 years ago
State if the two triangles are congruent. If they are, prove by using a two column proof!!!
Goshia [24]

Answer:

Step-by-step explanation:

There are four axioms to prove the triangles are contruent.They are

SSS(side side side axiom)

SAS(side angle side axiom)

AAS(angle angle side axiom)

ASA(angle side angle axiom)

RHS (right angle hypotenuse side axiom)

here two triangles are congruent by RHS axiom

3 0
2 years ago
Help I will be marking brainliest!<br><br> A. 65.99<br> B. 70.19<br> C. 52<br> D. 65.52
natita [175]

Answer:

65.992

Step-by-step explanation:

LM/PL = RN/QR

LM / 113 = 73/ 125

LM =(73/125) * 113

5 0
2 years ago
Read 2 more answers
If f(x) = x + 4 and g(x)=x^2-1, what is m(g o f)(x)?
Andreas93 [3]

Until now, given a function  f(x), you would plug a number or another variable in for x. You could even get fancy and plug in an entire expression for x. For example, given  f(x) = 2x + 3, you could find f(y2 – 1) by plugging y2 – 1 in for x to get f(y2 – 1) = 2(y2 – 1) + 3 = 2y2 – 2 + 3 = 2y2 + 1.

In function composition, you're plugging entire functions in for the x. In other words, you're always getting "fancy". But let's start simple. Instead of dealing with functions as formulas, let's deal with functions as sets of (x, y) points:

Let f = {(–2, 3), (–1, 1), (0, 0), (1, –1), (2, –3)} and  

let g = {(–3, 1), (–1, –2), (0, 2), (2, 2), (3, 1)}.  

 

Find (i) f (1), (ii) g(–1), and (iii) (g o f )(1).

(i) This type of  exercise is meant to emphasize that the (x, y) points are really (x, f (x)) points. To find  f (1), I need to find the (x, y) point in the set of (x, f (x)) points that has a first coordinate of x = 1. Then f (1) is the y-value of that point. In this case, the point with x = 1 is (1, –1), so:

8 0
3 years ago
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Someone please help :)<br> Both pls :)) also ill try Mark u brainliest &lt;33 please answer both :3
Svetradugi [14.3K]

Step-by-step explanation:

5. 56÷4 = 14

6. (2 × 27) - 3 × 5 - 8

54 - 15 - 8

39 - 8 = 31 ans.

Hope this answer helps you!

5 0
1 year ago
Read 2 more answers
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