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3 years ago

14

Please help lol, im on a math test

1 answer:

Sveta_85 [38]3 years ago

5 0

I know for sure it’s not B or D so I believe it is A.

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Darya [45]

Answer:

when you round it it would equal to around 29.03 so its...

64lbs = 29.03kg

4 0

2 years ago

Penelope is 4 times as old as Jose. Jose is 3 years older than Eliot. If the sum of all three is 57 years, how old will Jose tur

andrezito [222]

Jose is 13 and a half, Penelope is 40 and a half, and Eliot could be 3 years old. Jose would turn seventeen and a half in 4 years

3 0

3 years ago

A rectangle has a length 6 more than it's width if the width is decreased by 2 and the length decreased by 4 the resulting has a

Rashid [163]

Answer:

Length of original rectangle: 11 units.

$\frac{\text{Area of original rectangle}}{\text{Area of new rectangle}}=\frac{55}{21}$

$\text{Perimeter of new rectangle}=20$

Step-by-step explanation:

Let x represent width of the original rectangle.

We have been given that a rectangle has a length 6 more than it's width. S the length of the original rectangle would be $x+6$ .

We have been given that when the width is decreased by 2 and the length decreased by 4 the resulting has an area of 21 square units.

The width of new rectangle would be $x-2$ .

The length of new rectangle would be $x+6-4=x+2$ .

The area of new rectangle would be $(x+2)(x-2)$ .

Now we will equate area of new rectangle with 21 and solve for x as:

$(x+2)(x-2)=21$

Applying difference of squares, we will get:

$x^2-2^2=21$

$x^2-4=21$

$x^2-4+4=21+4$

$x^2=25$

Since width cannot be negative, so we will take positive square root of both sides.

$\sqrt{x^2}=\sqrt{25}$

$x=5$

Therefore, the width of original rectangle is 5 units.

Length of the original rectangle would be $x+6\Rightarrow x+5=11$ .

Therefore, the length of original rectangle is 11 units.

$\text{Area of original rectangle}=5\times 11$

$\text{Area of original rectangle}=55$

Therefore, area of the original rectangle is 55 square units.

Now we will find ratio of the original rectangle area to the new rectangle area as:

$\frac{\text{Area of original rectangle}}{\text{Area of new rectangle}}=\frac{55}{21}$

We know that perimeter of rectangle is two times the sum of length and width.

$\text{Perimeter of new rectangle}=2((x+2)+(x-2))$

$\text{Perimeter of new rectangle}=2((5+2)+(5-2))$

$\text{Perimeter of new rectangle}=2(7+3)$

$\text{Perimeter of new rectangle}=2(10)$

$\text{Perimeter of new rectangle}=20$

Therefore, the perimeter of the new rectangle is 20 units.

7 0

3 years ago

To eliminate the y-terms and solve for x in the fewest steps, by which constants should the equations be multiplied by before ad

Kryger [21]

Answer:

The first equation should be multiplied by 9 and the second equation by −4

Step-by-step explanation:

Given the simultaneous equation

First Equation: 5x − 4y = 28

Second equation: 3x - 9y = 30

In order to eliminate y, we must make the coefficient of x in both expression to be equal.

To do that the first equation should be multiplied by 9 (negative value of the coefficient of y in equation 2)and the second equation by -4( (coefficient of y in equation 1)

7 0

3 years ago

Find the equation of the linear function represented by the table below in slope-

vodomira [7]

Answer:

y = x + 4

Step-by-step explanation:

Let the equation of the linear function represented by the table is,

$y-y_1=m(x-x_1)$

where m = slope of the line

And this line passes through the points $(x_1,y_1)$ and $(x_2,y_2)$

Slope of the given line = $\frac{y_2-y_1}{x_2-x_1}$

From the given table two points lying on the function are (-4, 0) and (1, 5).

Slope 'm' = $\frac{5-0}{1+4}$ = 1

Therefore, equation of the linear function passing through (1, 5) and slope 1 will be,

y - 5 = (x - 1)

y = x + 5 - 1

y = x + 4

8 0

3 years ago