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3 years ago

Please help me I need it ASAP

Mathematics

1 answer:

LiRa [457]3 years ago

7 0

Step-by-step explanation:

the domain is the interval of x (input) values.

the range is the interval of y (result) values.

a) I would not guess (-3, 5). because -3 for x is at the beginning of the interval. and the end values of y (range) are -4 and 7 - not close enough to 5 to make me make a guess.

b) (2, 5) : 2 is closer to 5 end of the x interval, and 5 is closer to the 7 end of the y interval, so, this is closer correlated, and I could dare a guess.

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The Robotics Manufacturing Company operates an equipment repair business where emergency jobs arrive randomly at the rate of thr

cluponka [151]

Answer:

The correct answer is:

$\lambda=0.375 \ jobs \ per \ hour$
$\mu=0.5 \ jobs \ per \ hour$

Step-by-step explanation:

The given values are:

Service time varies,

Repair time = 2 hours

Standard deviation = 1.5 hours

Robotics uses per hour cost,

= $35

Company's cost per hour,

= $28

(a)

⇒ Arrival rate = Jobs per hours

then,

= $\frac{8 \ hours}{3 \ jobs}$

= $2.666 \ hours \ per \ job$

The jobs per hour will be:

⇒ $\lambda=\frac{1}{2.666}$

$=0.375$

(b)

⇒ Service rate = jobs per hour

then,

μ = $\frac{1 \ repair \ job}{2 \ hours}$

= $0.5 \ jobs$

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3 years ago

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8090 [49]

The answer is 103 it's false

3 0

3 years ago

The lowest temperature ever recorded at Oymyakon in Russia was 96.2°F below 0°F. The lowest temperature ever recorded at Prospec

Alekssandra [29.7K]

Answer:

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Step-by-step explanation:

If the temperature is x° F below 0° F then the thermometer reading is -x° F

It is given that the Lowest temperature recorded at Oymyakon in Russai was 96.2°F below 0°F

So the thermometer reading of the lowest recorded temperature at Oymyakon was -96.2° F

Also it is given that the Lowest temperature recorded at Prospect Creek in Alaska was 80°F below 0° F

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Aneli [31]

$| x | + 3 > 4\\
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chubhunter [2.5K]

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ \sqrt{7}}}\quad ,&{{ -\sqrt{2}}})\quad 
% (c,d)
&({{4\sqrt{7}}}\quad ,&{{ 5\sqrt{2}}})
\end{array}~~~
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
$

$\bf d=\sqrt{[4\sqrt{7}-\sqrt{7}]^2~+~[5\sqrt{2}-(-\sqrt{2})]^2}
\\\\\\
d=\sqrt{(4\sqrt{7}-\sqrt{7})^2~+~(5\sqrt{2}+\sqrt{2})^2}\implies d=\sqrt{(3\sqrt{7})^2~+~(6\sqrt{2})^2}
\\\\\\
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\\\\\\
\begin{cases}
135=5\cdot 3\cdot 3\cdot 3\\
\qquad 5\cdot 3^2\cdot 3\\
\qquad 15\cdot 3^2
\end{cases}\implies d=\sqrt{15\cdot 3^2}\implies d=3\sqrt{15}$

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3 years ago