Answer:
a) 48.21 %
b) 45.99 %
c) 20.88 %
d) 42.07 %
e) 50 %
Note: these values represent differences between z values and the mean
Step-by-step explanation:
The test to carry out is:
Null hypothesis H₀ is μ₀ = 30
The alternative hypothesis m ≠ 30
In which we already have the value of z for each case therefore we look directly the probability in z table and carefully take into account that we had been asked for differences from the mean (0.5)
a) z = 2.1 correspond to 0.9821 but mean value is ubicated at 0.5 then we subtract 0.9821 - 0.5 and get 0.4821 or 48.21 %
b) z = -1.75 P(m) = 0.0401 That implies the probability of m being from that point p to the end of the tail, the difference between this point and the mean so 0.5 - 0.0401 = 0.4599 or 45.99 %
c) z = -.55 P(m) = 0.2912 and this value for same reason as before is 0.5 - 0.2912 = 0.2088 or 20.88 %
d) z = 1.41 P(m) = 0.9207 0.9207 -0.5 0.4207 or 42.07 %
e) z = -5.3 P(m) = 0 meaning there is not such value in z table is too small to compute and difference to mean value will be 0.5
d) z= 1.41 P(m) =
5x = -2x
5x + 2x = 0
7x = 0
x = 0
the cheap answer is simply
(x-5)(x²+4x-2)
we can simply multiply the terms on one by the terms of the other and then add like-terms and simplify.
![\bf (x-5)(x^2+4x-2)\implies \begin{array}{cllll} x^2+4x-2\\ \times x\\ \cline{1-1}\\ x^3+4x^2-2x \end{array}+ \begin{array}{cllll} x^2+4x-2\\ \times -5\\ \cline{1-1}\\ -5x^2-20x+10 \end{array} \\\\\\ x^3+4x^2-2x-5x^2-20x+10\implies x^3+4x^2-5x^2-2x-20x+10 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill x^3-x^2-22x+10~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%28x-5%29%28x%5E2%2B4x-2%29%5Cimplies%20%5Cbegin%7Barray%7D%7Bcllll%7D%20x%5E2%2B4x-2%5C%5C%20%5Ctimes%20x%5C%5C%20%5Ccline%7B1-1%7D%5C%5C%20x%5E3%2B4x%5E2-2x%20%5Cend%7Barray%7D%2B%20%5Cbegin%7Barray%7D%7Bcllll%7D%20x%5E2%2B4x-2%5C%5C%20%5Ctimes%20-5%5C%5C%20%5Ccline%7B1-1%7D%5C%5C%20-5x%5E2-20x%2B10%20%5Cend%7Barray%7D%20%5C%5C%5C%5C%5C%5C%20x%5E3%2B4x%5E2-2x-5x%5E2-20x%2B10%5Cimplies%20x%5E3%2B4x%5E2-5x%5E2-2x-20x%2B10%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20x%5E3-x%5E2-22x%2B10~%5Chfill)
There are 30 new cars and 90 used cars in the dealership.
120/4=30 new
120-30=90 used
