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ZanzabumX [31]
3 years ago
8

A potential customer wants to find out how blockchain can benefit their company and why they should use Accenture’s Multi-party

Systems practice.
Which factor describes the value of using Accenture’s Multi-party Systems practice?
Computers and Technology
1 answer:
grandymaker [24]3 years ago
6 0

Answer:

maybe blockchain can help them in term of security

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the increase and decrease font button and the change text colour button (as shown in the picture )are include in which group ?​
denpristay [2]

Answer:

These are the part of FONT Group on MS word / Excel application where you can increase and decrease font, change text color, highlight text, select font from the list and many other functions.

You can also perform advance functions related to Font by clicking on a small arrow like icon in bottom right corner.

5 0
3 years ago
Kiera is building a new computer and wants to make sure she has an adequate power supply for all the new equipment she is purcha
VikaD [51]
700w power supply is very adequate
7 0
3 years ago
Read 2 more answers
Complete the method/function so that it converts dash/underscore delimited words into camel casing. The first word within the ou
nata0808 [166]

Answer:

I am writing a Python program. Let me know if you want the program in some other programming language.

def toCamelCase(str):  

   string = str.replace("-", " ").replace("_", " ")  

   string = string.split()

   if len(str) == 0:

       return str

   return string[0] + ''.join(i.capitalize() for i in string[1:])

   

print(toCamelCase("the-stealth-warrior"))

Explanation:

I will explain the code line by line. First line is the definition of  toCamelCase() method with str as an argument. str is basically a string of characters that is to be converted to camel casing in this method.

string = str.replace("-", " ").replace("_", " ") . This statement means the underscore or dash in the entire are removed. After removing the dash and underscore in the string (str), the rest of the string is stored in string variable.  

Next the string = string.split()  uses split() method that splits or breaks the rest of the string in string variable to a list of all words in this variable.

if len(str) == 0 means if the length of the input string is 0 then return str as it is.

If the length of the str string is not 0 then return string[0] + ''.join(i.capitalize() for i in string[1:])  will execute. Lets take an example of a str to show the working of this statement.

Lets say we have str = "the-stealth-warrior". Now after removal of dash in by replace() method the value stored in string variable becomes the stealth warrior. Now the split() method splits this string into list of three words the, stealth, warrior.

Next return string[0] + ''.join(i.capitalize() for i in string[1:])  has string[0] which is the word. Here join() method is used to join all the items or words in the string together.

Now i variable moves through the string from index 1 and onward and keeps capitalizing the first character of the list of every word present in string variable from that index position to the end.  capitalize() method is used for this purpose.

So this means first each first character of each word in the string starting from index position 1 to the end of the string is capitalized and then all the items/words in string are joined by join() method. This means the S of stealth and W of warrior are capitalized and joined as StealthWarrior and added to string[0] = the which returns theStealthWarrior in the output.

3 0
3 years ago
Please explain this code line by line and how the values of each variable changes as you go down the code.
Scilla [17]

Answer:

hope this helps. I am also a learner like you. Please cross check my explanation.

Explanation:

#include

#include

using namespace std;

int main()

{

int a[ ] = {0, 0, 0};  //array declared initializing a0=0, a1=0, a3=0

int* p = &a[1]; //pointer p is initialized it will be holding the address of a1 which means when p will be called it will point to whatever is present at the address a1, right now it hold 0.

int* q = &a[0];  //pointer q is initialized it will be holding the address of a0 which means when q will be called it will point to whatever is present at the address a0, right now it hold 0.

q=p; // now q is also pointing towards what p is pointing both holds the same address that is &a[1]

*q=1 ; //&a[0] gets overwritten and now pointer q has integer 1......i am not sure abut this one

p = a; //p is now holding address of complete array a

*p=1; // a gets overwritten and now pointer q has integer 1......i am not sure abut this one  

int*& r = p; //not sure

int** s = &q; s is a double pointer means it has more capacity of storage than single pointer and is now holding address of q

r = *s + 1; //not sure

s= &r; //explained above

**s = 1; //explained above

return 0;

}

6 0
3 years ago
Code a call to the function anotherFunc passing the array myints.
mario62 [17]

Answer:

d)anotherFunc(myints);

Explanation:

When we call a function we just have to pass the names of the arguments to the function.In case of arrays we also just have to pass the name of the array.We don't have to worry about the square brackets.So the function call will be like this.

anotherFunc(myints);

Hence the answer is option d.

4 0
3 years ago
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