Answer: ....
Ok done. Thank to me :>
The ratio of the measure of three angles of a triangle is 2:3:10. Find the measure of the largest angle.
2 answers:
Answer:
120 degrees
Step-by-step explanation:
Let the constant of proportionality between the angles of the given triangle be x.
Hence,
The Measure of The First Angle = 2x
The Measure of The Second Angle = 3x
The Measure of The Third Angle = 10x
The Angle Sum Property Of A Triangle says that the sum of all angles of any triangle is 180.
Hence,
As the Constant Of Proportionality obtained is 12
Hence,
The Measure of The First Angle = 2*12 = 24
The Measure of The Second Angle = 3*12 = 36
The Measure of The Third Angle = 10*12 = 120
As The Third Angle is the largest, its measure is 120.
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Given that ∠B ≅ ∠C.
to prove that the sides AB = AC
This can be done by the method of contradiction.
If possible let AB =AC
Then either AB>AC or AB<AC
Case i: If AB>AC, then by triangle axiom, Angle C > angle B.
But since angle C = angle B, we get AB cannot be greater than AC
Case ii: If AB<AC, then by triangle axiom, Angle C < angle B.
But since angle C = angle B, we get AB cannot be less than AC
Conclusion:
Since AB cannot be greater than AC nor less than AC, we have only one possibility. that is AB =AC
Hence if angle B = angle C it follows that
AB = AC, and AB ≅ AC.
Answer:
$ 7.7
Step-by-step explanation:
Given,
There are 18 $1 bills, ten $5 bills, eight $10 bills, three $20 bills, and one $100 bill,
Total number of bills = 18 + 10 + 8 + 3 + 1 = 40,
Thus,
The probability of $ 1 =
The probability of $ 5 =
The probability of $ 10 =
The probability of $ 20 =
The probability of $ 100 =
If a bill is selected randomly,
The expected value of the bill
= $ 7.7