1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Minchanka [31]
3 years ago
10

Which polynomial has (3x + 2) as a binomial factor?

Mathematics
2 answers:
jolli1 [7]3 years ago
9 0

Answer:

Option B.

Step-by-step explanation:

vlabodo [156]3 years ago
8 0

Answer:

its option B : 18x3 – 12x2 + 9x – 6

Step-by-step explanation:

12( \frac{ -2 }{3}) {}^{2} +23( \frac{ - 2}{3} )+10= \frac{16}{3} − \frac{46}{3} +10=0

You might be interested in
QUESTION 2<br><br> Which graph could be used to represent a non-proportional situation?
madreJ [45]
The one that doesn’t go through the origin
6 0
3 years ago
PLZ HELP !!!!!! IT’S DUE TODAY
Kay [80]

Answer:

jvhhhhchgcgvvv

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
In a bag of sweets, 6 are orange and 9 are lime. Jodi chooses a sweet at random, eats it an
Digiron [165]

Answer:\frac{17}{35}

Step-by-step explanation:

Given

The bag contains 6 orange and 9 lime sweets

For both sweets of the same flavor, Jodi must either choose orange or lime

No. of ways it can be done is ^6C_1\times^5C_1+^9C_1\times^8C_1

The total no of ways of selecting two sweets out of 15 is ^{15}C_1\times^{14}C_1

The probability that both sweets are the same flavor

P=\dfrac{^6C_1\times^5C_1+^9C_1\times^8C_1}{^{15}C_1\times^{14}C_1}=\frac{102}{210}=\frac{51}{105}=\frac{17}{35}

3 0
3 years ago
In a recent poll, 778 adults were asked to identify their favorite seat when they fly, and 492 of them chose a window seat. Use
seropon [69]

Answer:

Null hypothesis:p \leq 0.5  

Alternative hypothesis:p > 0.5  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

p_v =P(Z>7.36)=9.19x10^{-14}  

Since the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of adults prefer window seats when they fly is significantly higher than 0.5 .  

Step-by-step explanation:

1) Data given and notation

n=778 represent the random sample taken

X=492 represent the people that chose a window seat.

\hat p=\frac{492}{778}=0.632 estimated proportion of people that chose a window seat.

p_o=0.5 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the majority of adults prefer window seats when they fly:  

Null hypothesis:p \leq 0.5  

Alternative hypothesis:p > 0.5  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.632 -0.5}{\sqrt{\frac{0.5(1-0.5)}{778}}}=7.36  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>7.36)=9.19x10^{-14}  

5) Conclusion

Since the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of adults prefer window seats when they fly is significantly higher than 0.5 .  

6 0
3 years ago
IM WASTING MY POINTS FEEL FREE TO ANSWER OR TO SAY ANYTHING RANDOM BUT NOT inappropriate LOL ANYONE TO ANSWER FASTEST GETS BRAIN
DaniilM [7]

Answer:

hihihihihihihihihih hehe

Step-by-step explanation:

4 0
3 years ago
Other questions:
  • How do you calculate domain and range
    6·1 answer
  • What’s the product of 0.54(8)
    6·1 answer
  • Which equation has exactly one solution?
    13·1 answer
  • Addison budgets $120 for circus training. She buys a book about the art of juggling for $12 and pays $25 per circus class. Write
    9·1 answer
  • Laura painted her room with pink paint that was made by mixing paint at a ratio of 5 parts white paint to 2 parts red paint. Wil
    10·1 answer
  • What is the slope of the line that passes through the given points? (1 point)
    10·1 answer
  • Convert the decimal to a fraction in simplest form.<br><br>0.0625 =
    15·1 answer
  • How many times can 200 go into 487
    13·1 answer
  • Rayna and her husband have 8 niedes, 9 nephews, 6 cousins, 3 aunts, and 5 uncles. Eplain how you could use the fundamental count
    11·2 answers
  • Which of the sets of ordered pairs represents a function?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!