All categories

3 years ago

True or false solids possess a greater level of kinetic energy than gases

Physics

1 answer:

Kipish [7]3 years ago

8 0

Answer:

False

Explanation:

Solid particles have the least amount of energy, and gas particles have the greatest amount of energy. The temperature of a substance is a measure of the average kinetic energy of the particles. A change in phase may occur when the energy of the particles is changed.

You might be interested in

Which of the following is a trend in the health sciences

forsale [732]

Answer

more patient-centered care / advancing technology / integrative medicine

5 0

3 years ago

Read 2 more answers

A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 4.1 m/s. The car is a distanc

Igoryamba

It's 61.5m

by solving simultaneously equations
29+d = 6t (bear)
d=4.1t (tourist)

6 0

3 years ago

Read 2 more answers

The average speed of sound in water is 1500 m/s. how long would it take a sound wave to travel 9000 m? your answer

ryzh [129]

1500m = 1 sec

9000m/1500 = 6

So, it would take 6 sec to go 9000m

7 0

4 years ago

What are the magnitude Δ v and angle θ of the change in velocity if the initial velocity is 50.0 m/s south and the final velocit

I am Lyosha [343]

Answer:

∆v = 61.0 m/s

θ = 305°

Explanation:

Given;

initial velocity u= 50.0 m/s angle 270°

Final velocity v = 35.0 m/s angle 180°

∆v = v - u ........1

Resolving into x and y axis;

For y axis

∆vy = vsin180 - usin270

∆vy = 0 - (-50) = 50 m/s

x axis;

∆vx = vcos180 - ucos270

∆vx = -35 - 0= -35m/s

Magnitude of ∆v;

∆v = √(-35^2 + 50^2)

∆v = 61.0 m/s

Direction;

Tanθ = ∆vy/∆vx

θ = taninverse (50/-35)

θ = -55°

θ = 360-55 = 305°

5 0

4 years ago

Could someone help me to solve this que?

Rashid [163]

Answer:

The speed of the ball B is 6.4 m/s. The direction is 50 degrees counterclockwise.

Explanation:

Assuming the collision is elastic, use the conservation of momentum to solve this problem. The conservation law implies that:

$m\vec v_{A0}+m\vec v_{B0} = m\vec v_{A1}+m\vec v_{B1}$

(the total momentum of the two balls is the same before (index 0) and after (index 1) the collision). Since B is stationary and A and B have the same mass, this simplifies to:

$\vec v_{A0} = \vec v_{A1}+\vec v_{B1}$

and allows us to determine the velocity of ball B after the collision:

$\vec v_{B1} = \vec v_{A0}-\vec v_{A1}$

The above involves vectors. Your problem suggests to use the component method, which I am assuming means solving the above equation separately along the x and y axes. Define x to align with the original line of motion of the ball A before the collision, and y to be perpendicular to x, pointing up:

$v_{B1x} = v_{A0x}-v_{A1x}\\v_{B1y} = v_{A0y}-v_{A1y}$

We just need to compute the x- and y-components of the known velocity of the ball A. Drs. Sine and Cosine come to help here.

$v_{A1x} = |v_{A1}|\cos 40^\circ\\v_{A1y} = |v_{A1}|\sin 40^\circ$

$v_{B1x} = |v_{A0}|\cos 0^\circ-|v_{A1}|\cos 40^\circ=(10.0-7.7\cdot 0.77) \frac{m}{s}\approx 4.1\frac{m}{s}\\v_{B1y} = |v_{A0}|\sin 0^\circ-|v_{A1}|\sin 40^\circ=(0-7.7\cdot 0.64) \frac{m}{s}\approx -4.9\frac{m}{s}$

The speed of the ball B is $|v_{B1}| = \sqrt{4.1^2+(-4.9)^2}\frac{m}{s}\approx 6.4 \frac{m}{s}$ . The direction (angle from horizontal) is $\beta = \arcsin (-\frac{4.9}{6.4})\approx -50^\circ$ , i.e., 50 degrees counterclockwise.

7 0

3 years ago

True or false solids possess a greater level of kinetic energy than gases ​

True or false solids possess a greater level of kinetic energy than gases