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AURORKA [14]
3 years ago
11

A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 4.1 m/s. The car is a distanc

e d away. The bear is 29 m behind the tourist and running at 6.0 m/s. The tourist reaches the car safely. What is the maximum possible value for d?
Physics
2 answers:
Igoryamba3 years ago
6 0
It's 61.5m

by solving simultaneously equations  
29+d = 6t   (bear)
d=4.1t          (tourist)


vodomira [7]3 years ago
5 0
<span>A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 4.1 m/s. The car is a distance d away. The bear is 29 m behind the tourist and running at 6.0 m/s. The tourist reaches the car safely. What is the maximum possible value for d?
</span>
61.5m
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Crazy boy [7]

Answer:

Approximately 7.3 \times 10^{-3}\; \rm A (approximately 7.3\; \rm mA) assuming that the magnetic field and the wire are both horizontal.

Explanation:

Let \theta denote the angle between the wire and the magnetic field.

Let B denote the magnitude of the magnetic field.

Let l denote the length of the wire.

Let I denote the current in this wire.

The magnetic force on the wire would be:

F = B \cdot l \cdot I \cdot \sin(\theta).

Because of the \sin(\theta) term, the magnetic force on the wire is maximized when the wire is perpendicular to the magnetic field (such that the angle between them is 90^\circ.)

In this question:

  • \theta = 20^\circ (or, equivalently, (\pi / 9) radians, if the calculator is in radian mode.)
  • B = 3\; \rm mT = 3 \times 10^{-3}\; \rm T.
  • l = 6\; \rm cm = 6 \times 10^{-2}\;\rm m.
  • F = 1.5\times 10^{-4}\; \rm N.

Rearrange the equation F = l \cdot I \cdot \sin(\theta) to find an expression for I, the current in this wire.

\begin{aligned} I &= \frac{F}{l \cdot \sin(\theta)} \\ &= \frac{3\times 10^{-3}\; \rm T}{6 \times 10^{-2}\; \rm m \times \sin \left(20^{\circ}\right)} \\ &\approx 7.3 \times 10^{-3}\; \rm A = 7.3 \; \rm mA\end{aligned}.

5 0
2 years ago
Suppose that the moment of inertia of a skater with arms out and one leg extended is 3.5 kg⋅m2 and for arms and legs in is 0.70
Aleksandr-060686 [28]
Given:
I₁ = 0.70 kg-m², the moment of inertia with arms and legs in
I₂ = 3.5 kg-m², the moment of inertia with arms and a leg out.
ω₁ = 4.8 rev/s, the angular speed with arms and legs in.
That is,
ω₁ = (4.8 rev/s)*(2π rad/rev) = 30.159 rad/s

Let ω₂ =  the angular speed with arms and a leg out.
Because momentum is conserved, therefore
I₂ω₂ = I₁ω₁
ω₂ = (I₁/I₂)ω₁
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ω₂ = (6.032 rad/s)*(1/(2π) rev/rad) = 0.96 rev/s

Answer: 0.96 rev/s


3 0
3 years ago
A baseball of mass 0.143 kg is thrown from the roof of a building 23.1 m above the ground. Its initial velocity is 37.6 m/s at a
Olin [163]

Answer:

A 0.17 kg baseball is launched from the roof of a building 14 m above the ground. Its initial velocity is 29 m/s at 40° above the horizontal. Assume any effects of air resistance are negligible.

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A baby stroller is a rest on top of a hill which is 10 m high. The stroller and baby have a mass of 20 kg. What is the potential
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PE=mgh

<em>where:</em>

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  • g: the acceleration due to the gravity in m/s^2
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PE=20*9.8*10=1960 J

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A 2.17 g sample of acetylsalicylic acid required 23.88 mL of 0.5043 M NaOH for complete reaction. Addition of 13.46 mL of 0.4472
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Answer:

The pH of the mixture is 0.7926

Explanation:

Hi there!

The acetylsalicylic acid was completely neutralized by the sodium hydroxide so that the only protons present in the solution come from the HCl. The volume of the solution can be calculated as the addition of the volume of sodium hydroxide and the volume of HCl (assuming that the mixture is an ideal solution).

The number of moles of HCl added can be calculated as follows:

13.46 ml (0.4472 mol/1000 ml) = 6.019 × 10⁻³ mol

The volume of the solution is 13.46 ml + 23.88 ml = 37.34 ml

Then, we can calculate the concetration of protons in the solution:

[H] = 6.019 × 10⁻³ mol /0.03734 l = 0.1612 M

The pH of the mixture:

pH = -log[H]

pH = -log[0.1612] = 0.7926

4 0
3 years ago
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