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dedylja [7]
3 years ago
8

Janet jumps horizontally off a high diving platform with a velocity of 2.63 m/s and lands in the water 1.9 s later. How high is

the platform
Physics
1 answer:
soldier1979 [14.2K]3 years ago
5 0

Answer:

The height of the platform is 22.686 m.

Explanation:

Given;

initial velocity of Janet, u = 2.63 m/s

time of her motion, t = 1.9 s

The height of the platform is given by;

h = ut + ¹/₂gt²

substitute the given values and solve for height "h"

h = (2.63 x 1.9) + ¹/₂(9.8)(1.9)²

h = 4.997 + 17.689

h = 22.686 m

Therefore, the height of the platform is 22.686 m.

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2 years ago
Which statement below best describes the relationship between the voltage, resistance, and current?
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Answer:

As voltage increases, current increases and resistance stays the same .

Explanation:

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3 years ago
State the methods of nuclear fission waste disposal and the suitability of each method.
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5 0
3 years ago
A student at a window on the second floor of a dorm sees her physics professor walking on the sidewalk beside the building. she
klasskru [66]
Refer to the diagram shown below.

In order for the balloon to strike the professor's head, th balloon should drop by 18 - 1.7 = 16.3 m in the time at the professor takes to walk 1 m.
The time for the professor to walk 1 m is
t = (1 m)/(0.45 m/s) = 2.2222 s

The initial vertical velocity of the balloon is zero.
The vertical drop of the balloon in 2.2222 s is
h = (1/2)*(9.8 m/s²)*(2.2222 s)² = 24.197 m

Because 24.97 > 16.3, the balloon lands in front of the professor, and does not hit the professor.

The time for the balloon to hit the ground is
(1/2)*(9.8)*t² = 18
t = 1.9166 s

The time difference is 2.2222 - 1.9166 = 0.3056 s
Within this time interval, the professor travels 0.45*0.3056 = 0.175 m
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Answer: 
The balloon misses the professor, and falls 0.175 m in front of the professor.

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3 years ago
Select the correct answer.
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Answer:

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