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bonufazy [111]
4 years ago
15

The average speed of sound in water is 1500 m/s. how long would it take a sound wave to travel 9000 m? your answer

Physics
1 answer:
ryzh [129]4 years ago
7 0
1500m = 1 sec

9000m/1500 = 6

So, it would take 6 sec to go 9000m
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(Need help pls)!!!!! <br><br><br>​
Rainbow [258]

Answer:

I assume they want answer A, but it's a silly question.

Explanation:

Well, if we assume that the girls are applying equal force, as they are the same size and strength (apparently also the same resolve etc.).

Equal force in opposite directions means the composite force is null. An object that no force is applied to continues moving in the same direction, so if the doll was moving somewhere, it would keep doing so, except all of this makes no sense the doll is not in gravityless vacuum what are we even talking about.

The answer A is the least ridiculous.

8 0
3 years ago
A certain radioactive nuclide decays with a disintegration constant of 0.0178 h-1.
umka21 [38]

Explanation:

Given that,

The disintegration constant of the nuclide, \lambda=0.0178\ h^{-1}

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t_{1/2}=\dfrac{ln(2)}{\lambda}

t_{1/2}=\dfrac{ln(2)}{0.0178}

t_{1/2}=38.94\ h

(b) The decay equation of any radioactive nuclide is given by :

N=N_oe^{-\lambda t}

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Number of remaining sample in 4.44 half lives is :

t_{1/2}=4.44\times 38.94

t_{1/2}=172.89\ h^{-1}

So, \dfrac{N}{N_o}=e^{-0.0178\times 172.89}

\dfrac{N}{N_o}=0.046

(c) Number of remaining sample in 14.6 days is :

t_{1/2}=14.6\times 24

t_{1/2}=350.4\ h^{-1}

So, \dfrac{N}{N_o}=e^{-0.0178\times 350.4}

\dfrac{N}{N_o}=0.0019

Hence, this is the required solution.

4 0
4 years ago
find an expression for a moment of inertia of a thin rod rotating about an axis passing through its center perpendicular to it's
jenyasd209 [6]

the Axis Perpendicular to the Length and Passing through the Center. Take a uniform thin rod AB whose mass is M and length is l. YY’ axis passes through the center of the rod and perpendicular to the length of the rod. We have to calculate the moment of inertia about this axis. YY’.

Suppose, small piece dx is at a distance x from the YY' axis. Hence, mass of length dx is =(

l

M

)dx The moment of inertia of small piece about the YY' axis

dl=[(

l

M

)dx]x

2

Therefore, the moment of inertia of the complete rod about the YY' axis.

b) Moment of Inertia about the axis perpendicular to the the length and passing through the Corner If I

CD

is the moment of inertia about the axis CD perpendicular to the length of a thin rod and passing through the point A then, by theorem of parallel axis;

l

CD

=l

YY

′

+Md

2

=

12

Ml

2

+M(

2

l

)

2

l

CD

=

3

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.........(2)

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3 years ago
Describe how a unique position of the sun , earth, and moon creates a lunar eclipse
Serggg [28]
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Volume is measured in cubic centimeters. Hope this helped.
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