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3 years ago

The degree of the problem

Mathematics

1 answer:

Rina8888 [55]3 years ago

7 0

Answer: A. 5

Step-by-step explanation:

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Find xif f(x) = 2x + 7 and f(x) = -1.

Natali [406]

Answer: -4

Step-by-step explanation:

Solve 2x+7=-1

2x. =-8

x. =-4

8 0

3 years ago

Read 2 more answers

1.3485 divided by 0.31 please

levacccp [35]

The Answer Is 4.35. Hope This Helps.

6 0

3 years ago

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3(2x - 1) = 1/2 (4x - 2) + 2 What would it be?

Novay_Z [31]

Answer:

X = 1

Step-by-step explanation:

Just distribute properly, and distribute the fraction multiplying the numerator by 4 and 2

6 0

3 years ago

15. If x=a Sin2t (I+Cos2t) and y=b Cos 2t (1-Cos2t) then find dy/dx at =22/7*4

Sav [38]

By the chain rule,

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm dt}\dfrac{\mathrm dt}{\mathrm dx}\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm dt}}{\frac{\mathrm dx}{\mathrm dt}}$

It looks like we're given

$\begin{cases}x=a\sin(2t)(1+\cos(2t))\\y=b\cos(2t)(1-\cos(2t))\end{cases}$

where a and b are presumably constant.

Recall that

$\cos^2t=\dfrac{1+\cos(2t)}2$

$\sin^2t=\dfrac{1-\cos(2t)}2$

so that

$\begin{cases}x=2a\sin(2t)\cos^2t\\y=2b\cos(2t)\sin^2t\end{cases}$

Then we have

$\dfrac{\mathrm dx}{\mathrm dt}=4a\cos(2t)\cos^2t-4a\sin(2t)\cos t\sin t$

$\dfrac{\mathrm dy}{\mathrm dt}=-4b\sin(2t)\sin^2t+4b\cos(2t)\sin t\cos t$

$\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{4b\cos(2t)\sin t\cos t-4b\sin(2t)\sin^2}{4a\cos(2t)\cos^2t-4a\sin(2t)\cos t\sin t}$

$\implies\boxed{\dfrac{\mathrm dy}{\mathrm dx}=\dfrac ba\tan t}$

where the last reduction follows from dividing through everything by $\cos(2t)\cos^2t$ and simplifying.

I'm not sure at which point you're supposed to evaluate the derivative (22/7*4, as in 88/7? or something else?), so I'll leave that to you.

8 0

4 years ago

Consider the following equations x=4/t and y = 4-t^2 a. Solve the equation for y (eliminate the parameter.)

Nookie1986 [14]

Answer:

y=-16^a/x^2 + 4

Step-by-step explanation:

3 0

3 years ago