Write a cosine function that has a midline of 5 an amplitude of 2 and a period of 5/2

Mathematics

1 answer:

Nesterboy [21]3 years ago

6 0

Answer:

Uuy

Step-by-step explanation:

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Maximize the objective function P = 2x + 1.5y for the feasible region shown. State the maximum value for P and the ordered pair

umka2103 [35]

Incomplete question. However, let's assume this are feasible regions to consider:

Points:

- (0, 100)

- (0, 125)

- (0, 325)

- (1, 200)

Answer:

Maximum value occurs at 325 at the point (0, 325)

Step-by-step explanation:

Remember, we substitute the points value for x, y in the objective function P = 2x + 1.5y.

- For point (0, 100): P= 2(0) + 1.5 (100) =150

- For point (0, 125): P= 2(0) + 1.5 (125) =187.5

For point (0, 325): P= 2(0) + 1.5 (325) = 487.5

For point (1, 200): P= 2(1) + 1.5 (200) = 302

Therefore, we could notice from the above solutions that at point (0,325) we attain the maximum value of P.

7 0

3 years ago

What is 1 2/3 multiple 2/3

Flauer [41]

Answer:

$1\frac{1}{9}$

Step-by-step explanation:

Given the following question:

$1\frac{2}{3} \times\frac{2}{3}$

In order to multiply the two, we have to convert the mixed number into a improper fraction and then multiply the numerator by the numerator, the denominator by the denominator.

$1\frac{2}{3} =3\times1=3+2=\frac{5}{3}$
$\frac{5}{3} \times\frac{2}{3}$
$5\times2=10$
$3\times3=9$
$=\frac{10}{9}$

Convert the improper fraction into a mixed number:

$\frac{10}{9}$
$\frac{10}{9} =10\div9=1\frac{1}{9}$
$=1\frac{1}{9}$

Your answer is "1 1/9."

Hope this helps.