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Karolina [17]
2 years ago
11

Write a cosine function that has a midline of 5 an amplitude of 2 and a period of 5/2

Mathematics
1 answer:
Nesterboy [21]2 years ago
6 0

Answer:

Uuy

Step-by-step explanation:

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6sqrt20 + 8sqrt5 - 5sqrt45
marta [7]

Answer:

11.1803398875

Step-by-step explanation:

4 0
3 years ago
Shenise is a star player for her women's basketball team. She has injured her ankle, and it is doubtful that she will be able to
Sladkaya [172]

Answer:

<u>The correct answer is that it's expected the team will score 72 points.</u>

Step-by-step explanation:

1. This is the information given in the question:

When Shenise can play the team scores 91 points

Without Shenise the team just scores 60 points

Therefore, when Shenise is at her best, her 100%, she scores 31 points by herself. When she's not in conditions, she can't play.

2. For finding out how many points Shenise can score if she plays, we use this formula:

If Shenise is at her 100%, she scores 31 points, how many points can she score if she's at 40% chance of playing?

Points upcoming game = 31 * 40 / 100

Points upcoming game = 1,240 / 100

Points upcoming game = 12.40 = 12 (rounding to the nearest whole number)

3. If Shenise plays, she can score 12 points. Now, we can calculate how many points her team will score.

Points the team scores when Shenise doesn't play = 60

Points the team will score if Shenise plays = 60 + 12 = 72

<u>The team will probably score 72 points with a 40% chance that Shenise will play the upcoming game</u>

4 0
3 years ago
Solve the following system by any method -8x-8y=0 -8x+2y=-20
iVinArrow [24]
                     \fbox{Solution by using Matrix} 

\text{Linear Equation} = -8x-8y=0 , -8x+2y=-20

\text{Rewrite the linear equations above as a matrix} 

\left[\begin{array}{ccc}8&-8&0\\-8&2&-20\\\end{array}\right] 

\text{Apply to Row2 : Row2 + Row1} 

\left[\begin{array}{ccc}8&-8&0\\-8&-6&-20\\\end{array}\right] 

\text{ Simplify rows} 

\left[\begin{array}{ccc}8&-8&0\\0&1&10/3\\\end{array}\right] 

\text{Note: The matrix is now in echelon form.}\text{The steps below are for back substitution.} 

\text{Apply to Row1 : Row1 + 8 Row2} 

\left[\begin{array}{ccc}8&0&80/30\\0&1&10/3\\\end{array}\right] 

\text{ Simplify rows}  

\left[\begin{array}{ccc}1&0&10/3\\0&1&10/3\\\end{array}\right] 

\text{Therefore, the solution is} 

x= \dfrac{10}{3} \ \text{and} \ \ y=\dfrac{10}{3}
7 0
3 years ago
At age 25, you decide to start your retirement account, and put $700 at the end of each quarter into an account paying 7.25% com
Veronika [31]

Answer:

44.5 is the best

Step-by-step explanation:

3 0
3 years ago
Add. write your answer in simplest form.<br> -4 _/135 + 7 _/15
Zarrin [17]

\huge\quad\qquad\underline{{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \:  - 4 \sqrt{135} + 7 \sqrt{15}

\qquad \tt \dashrightarrow \: - 4 \sqrt{5 \times3 \times 3 \times 3}  + 7 \sqrt{15}

\qquad \tt \dashrightarrow \:( - 4 \times 3) \sqrt{5 \times 3}  + 7 \sqrt{15}

\qquad \tt \dashrightarrow \: - 12 \sqrt{15 }  + 7 \sqrt{15}

\qquad \tt \dashrightarrow \: - 5 \sqrt{15}

7 0
2 years ago
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