1320/5280 in the simplest form is 1/4
Hey there! :)
To find equivalent fractions, divide or multiply the numerator AND denominator by the same number.
Example: Multiply by 2
5 × 2 = 10
12 × 2 = 24
10/24
Example: Multiply by 3
5 × 3 = 15
12 × 3 = 36
15/36
Two fractions equivalent to 5/12 are:
- 10/24
- 15/36
Hope this helps :)
<span>There are several ways to do this problem. One of them is to realize that there's only 14 possible calendars for any year (a year may start on any of 7 days, and a year may be either a leap year, or a non-leap year. So 7*2 = 14 possible calendars for any year). And since there's only 14 different possibilities, it's quite easy to perform an exhaustive search to prove that any year has between 1 and 3 Friday the 13ths.
Let's first deal with non-leap years. Initially, I'll determine what day of the week the 13th falls for each month for a year that starts on Sunday.
Jan - Friday
Feb - Monday
Mar - Monday
Apr - Thursday
May - Saturday
Jun - Tuesday
Jul - Thursday
Aug - Sunday
Sep - Wednesday
Oct - Friday
Nov - Monday
Dec - Wednesday
Now let's count how many times for each weekday, the 13th falls there.
Sunday - 1
Monday - 3
Tuesday - 1
Wednesday - 2
Thursday - 2
Friday - 2
Saturday - 1
The key thing to notice is that there is that the number of times the 13th falls upon a weekday is always in the range of 1 to 3 days. And if the non-leap year were to start on any other day of the week, the numbers would simply rotate to the next days. The above list is generated for a year where January 1st falls on a Sunday. If instead it were to fall on a Monday, then the value above for Sunday would be the value for Monday. The value above for Monday would be the value for Tuesday, etc.
So we've handled all possible non-leap years. Let's do that again for a leap year starting on a Sunday. We get:
Jan - Friday
Feb - Monday
Mar - Tuesday
Apr - Friday
May - Sunday
Jun - Wednesday
Jul - Friday
Aug - Monday
Sep - Thursday
Oct - Saturday
Nov - Tuesday
Dec - Thursday
And the weekday totals are:
Sunday - 1
Monday - 2
Tuesday - 2
Wednesday - 1
Thursday - 2
Friday - 3
Saturday - 1
And once again, for every weekday, the total is between 1 and 3. And the same argument applies for every leap year.
And since we've covered both leap and non-leap years. Then we've demonstrated that for every possible year, Friday the 13th will happen at least once, and no more than 3 times.</span>
Answer:
(-6,4)
Step-by-step explanation:
1/3x − 2 = x + 2 is obtained by equating the following two functions:
y = (⅓)x - 2
y = x + 2
Graph:
Draw two straight lines
1) joining (0,-2) and (6,0)
2) joining (0,2) and (-2,0)
On the graph, you'll see that the above two lines intersect at: (-6,4)
Hence the solution is (-6,4)
Answer:
After 10 years the investment A will be bigger than investment B.
Step-by-step explanation:
In Investment A, 50 increases each year by 8% and in investment B, 60 increases by 3 each year.
If after x years the investment A will be equal to investment B, then we can write the equation as
⇒ 50 + 4x = 60 + 3x
⇒ x = 10
Therefore, after 10 years the investment A will be bigger than investment B. (Answer)