Answer:
The maximum emf that can be generated around the perimeter of a cell in this field is 
Explanation:
To solve this problem it is necessary to apply the concepts on maximum electromotive force.
For definition we know that

Where,
N= Number of turns of the coil
B = Magnetic field
Angular velocity
A = Cross-sectional Area
Angular velocity according kinematics equations is:



Replacing at the equation our values given we have that




Therefore the maximum emf that can be generated around the perimeter of a cell in this field is 
Answer:
When a rope supports the weight of an object that is at rest, the tension in the rope is equal to the weight of the object: T = mg.
Image result for I need help find how much tension is in the string???? And can you explain how you got it after you get the answer plz????
Hence, in such a case the tension will be equal to the centrifugal force.
Formula for tension = centrifugal force = mv2/r.
So the formula of tension will be = centripetal force – force of gravity = mv2/r – mg = m(v2/r-g)
The formula of tension will be = centripetal force + force of gravity = mv2/r + mg = m(v2/r+g)
Explanation:
When a moving charge is near a magnetic field, it experiences a force. The magnetic field has the ability to attract or repel charge in a magnetic field, and thus the moving charge will experience a force on it. Hope this helps.
Answer:
2.3 ×
Explanation:
1 kg = 1000 g.
0.00023 kg x 1000 g = 0.23 grams
Answer:
Therefore, the brick appears to have an additional force pushing it upward.
Explanation:
When a brick is submerged in the water, it has two forces acting upon it. One force is the gravitational force or the weight of the brick, that acts downward. The weight force also acts on the brick when it is not in water. But, in water an additional force acts on the brick. This additional force is named as Buoyant Force. This force is equal to the weight of the water displaced by the brick. And this Buoyant Force acts on the brick in the upward direction. The formula for this force is given as follows:
Buoyant Force = (Density of Water)(Volume of Water Displaced)(g)
<u>Therefore, the brick appears to have an additional force pushing it upward.</u>
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