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Zinaida [17]
3 years ago
14

Calculate the solubility (in m units) of ammonia gas in water at 298 k and a partial pressure of 2.50 bar . the henry's law cons

tant for ammonia gas at 298 k is 58.0 m/atm and 1 bar=0.9869 atm.
Physics
1 answer:
Eduardwww [97]3 years ago
8 0
Henry's Law (formulated in 1803 by William Henry) states that aa constant temperature, the amount of gas dissolved in a liquid is directly proportional to the partial pressure exerted by that gas on the liquid.
 Mathematically it can be formulated as
 C = H⨯P
 being:
 C: the molar concentration of dissolved gas A,
 P: the partial pressure of it
 H: Henry's constant
 Substituting:
 C = P * H
 C = (2.50 * 0.9869) * 58.0
 C = 143.1
 Answer:
 the solubility (in m units) is
 C = 143.1
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we substitute

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          M = \frac{4 \pi ^2  ( 2.3460 \ 10^7)^3 }{5.67 10^{-11} \ (1.0912 \ 10^5)^2 }

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